我想创建一个(PCRE)正则表达式以匹配所有常用的编号列表,并且我想分享自己的想法并收集输入信息的方式.
I'd like to create a (PCRE) regular expression to match all commonly used numbered lists, and I'd like to share my thoughts and gather input on way to do this.
我已将列表"定义为英国盎格鲁-撒克逊规范化规范集,即
I've defined 'lists' as the set of canonical Anglo-Saxon conventions, i.e.
1 2 3 1. 2. 3. 1) 2) 3) (1) (2) (3) 1.1 1.2 1.2.1 1.1. 1.2. 1.3. 1.1) 1.2) 1.3) (1.1) (1.2) (1.3)字母
a b c a. b. c. a) b) c) (a) (b) (c) A B C A. B. C. A) B) C) (A) (B) (C)罗马数字
i ii iii i. ii. iii. i) ii) iii) (i) (ii) (iii) I II III i. ii. iii. i) ii) iii) (i) (ii) (iii)我想知道列表的强度,是否应该有其他编号约定,以及是否应删除其中的任何编号.
I'd like to know how strong a set of list this is, and if there are other numbering conventions that should be in there, and if any of these ought to be removed.
这是我为解决此问题而创建的正则表达式(在 Python 中):
Here's a regular expression I've created to solve this problem (in Python):
numex = r'(?:\d{1,3}'\ # 1, 2, 3 '(?:\.\d{1,3}){0,4}'\ # 1.1, 1.1.1.1 '|[A-Z]{1,2}'\ # A. B. C. '|[ivxcl]{1,6}' # i, iii, ... rex = repile(r'(\(?%s\)|%s\.?)' % numex, re.I) # re.U? rex.match("123. Some paragraph")我想知道此正则表达式是否足以解决此问题,以及是否还有其他替代方法(正则表达式或其他方法).
I'd like to know how adequate this regex is for this problem, and if there are other alternative (regex or otherwise) solutions.
顺便说一句,对于我的特定用例,我预计列表编号不会超过25-50.
Incidentally, for my particular use-case, I wouldn't expect list numbers of more than 25-50.
感谢您阅读.
布莱恩
推荐答案以下是Wikified解决方案:
numex = r"""^(?: \d{1,3} # 1, 2, 3 (?:\.\d{1,3}){0,4} # 1.1, 1.1.1.1 | [B-H] | [J-Z] # A, B - Z caps at 26. | [AI](?!\s) # Note: "A" and "I" can properly start non-lists | [a-z] # a - z | [ivxcl]{1,6} # Roman ii, etc | [IVXCL]{1,6} # Roman IV, etc. ) """ rex = repile(r'^\s*(\(?%s\)|%s\.?)\s+(.*)' % (numex, numex), re.X)最欢迎添加,更改和建议.
Additions, changes and suggestions most welcome.
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正则表达式,用于匹配各种类型的编号列表
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