我需要解析Java的日期的RFC 2822字符串表示形式。一个示例字符串在这里:
I need to parse an RFC 2822 string representation of a date in Java. An example string is here:
2010年3月13日星期六11:29:05 -0800
Sat, 13 Mar 2010 11:29:05 -0800
看起来很讨厌,所以我想确保我正在做的一切正确,并会遇到奇怪的问题后,日期被解释错误通过AM-PM /军事时间问题,UTC时间问题,我不期待的问题等...
It looks pretty nasty so I wanted to make sure I was doing everything right and would run into weird problems later with the date being interpreted wrong either through AM-PM/Military time problems, UTC time problems, problems I don't anticipate, etc...
谢谢!
推荐答案这是一个快速的代码,可以做你所要求的(使用 SimpleDateFormat )
This is quick code that does what you ask (using SimpleDateFormat)
String rfcDate = "Sat, 13 Mar 2010 11:29:05 -0800"; String pattern = "EEE, dd MMM yyyy HH:mm:ss Z"; SimpleDateFormat format = new SimpleDateFormat(pattern); Date javaDate = format.parse(rfcDate); //Done.PS。我没有在这里处理异常和并发(因为SimpleDateFormat在解析日期时不同步)。
PS. I've not dealt with exceptions and concurrency here (as SimpleDateFormat is not synchronized when parsing date).
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