如何使用Apache HttpClient 4.2.1或>对网站进行身份验证?

本文介绍了如何使用Apache HttpClient 4.2.1或>对网站进行身份验证?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我是http编程的新手，正在尝试针对不使用API​​的网站进行身份验证，但遇到了一些麻烦.我发现了一些其他问题，这些问题似乎与我的相似，但是没有一个答案对我有用.

I'm new to http programming and I'm attempting to authenticate against a website that doesn't use an API and I'm having some trouble. I found a few other questions that seemed to be similar to mine, but none had an answer that worked for me.

我尝试了几种不同的方法，但是还没有找到一种可行的方法.实际上，我曾经为我工作过一次，但是没有签入该代码(我知道-我在想什么?).我无法再次回到该工作版本.到目前为止，我已经尝试过以下几点:

I've tried several different approaches but haven't found one that works yet. Actually, I had it work for me once, but didn't check in that code (I know - what was I thinking?). I haven't been able to get back to that working version again. Here are a few things that I've tried so far:

HttpClient client = new DefaultHttpClient(); //or any method to get a client instance, with a 'threadsafe' connection manager or otherwise Credentials credentials = new UsernamePasswordCredentials(userName, passwd); ((DefaultHttpClient) client).getCredentialsProvider() .setCredentials(AuthScope.ANY, credentials); // website is defined as my target website & this constitutes the valid login URL HttpPost post = new HttpPost(https + website + "/login"); HttpEntity entity = new StringEntity("Username="+ userName +"&Password="+ passwd); post.setEntity(entity); HttpResponse response = client.execute(post); EntityUtils.consume(entity); entity = response.getEntity(); EntityUtils.consume(entity); // the protected part of the site is over http after authentication succeeds HttpGet get = new HttpGet(http + website +"/protected"); response = client.execute(get); entity = response.getEntity(); String content = EntityUtils.toString(entity);

这时，我从网站上获得的实体"为错误":未经授权的访问".

At this point the 'entity' I get back from the website is "error":"Unauthorized Access."

您会注意到，我有一个'Credentials'实例正在传递给HttpClient，并且我还将用户名& HttpPost实体中的密码.我分别尝试了每种方法，它们都返回了错误":未经授权的访问".结果.

You'll notice that I have a 'Credentials' instance being passed to the HttpClient and I'm also putting the user name & password in the HttpPost entity. I tried each of these approaches separately and they both returned the "error":"Unauthorized Access." result.

我尝试了DefaultHttpClient，它使用一个单线程连接管理器以及"ThreadSafeClientConnManager"，但都没有起作用.

I've tried the DefaultHttpClient, which uses a single thread connection manager, as well as 'ThreadSafeClientConnManager' and neither worked.

推荐答案

首先尝试使用此url登录(将url复制到文本板或其他内容，然后再编辑):

first try to login using this url (copy the url to textpad or something first - then edit it):

www.centraldispatch/login?uri =％2Fprotected％2F& Username = XXX& Password = YYY

只需用您的真实用户/通行证替换XXX和YYY-确保它可以工作.

Just replace the XXX and YYY with your real user/pass - make sure it works.

然后使用:

List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(1); nameValuePairs.add(new BasicNameValuePair("Username","Your username")); nameValuePairs.add(new BasicNameValuePair("Password","Your password")); post.setEntity(new UrlEncodedFormEntity(nameValuePairs)); HttpResponse response = client.execute(post); BufferedReader rd = new BufferedReader(new InputStreamReader( response.getEntity().getContent())); String line = ""; while ((line = rd.readLine()) != null) { System.out.println(line); }