正则表达式，用于SimpleDateFormat字符串

本文介绍了正则表达式，用于SimpleDateFormat字符串的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我主要以 yyyy-MM-dd 和 yyyy-MM-dd hh:mm:ss 的形式约会.我想模式匹配 yyyy-MM-dd hh:mm:ss .

I have dates mainly in the forms of yyyy-MM-dd and yyyy-MM-dd hh:mm:ss. I want to pattern match yyyy-MM-dd hh:mm:ss.

为此目的编写正则表达式很简单吗?我是regex的新手，所以不胜感激任何资源达人都可以让我快速入门吗?

Is it trivial to write an regex for this purpose? I am new to regex so would appreciate any resource tat could get me up to speed?

推荐答案

如果要在字符串中查找这些日期符号，则正则表达式确实是一个不错的选择.您可以使用此正则表达式:

If you are trying to find these date notations in a String, then regexes is indeed a good choice. You could use this regex:

\b\d{4}-\d{2}-\d{2} \d{1,2}:\d{2}:\d{2}\b

在此处查看操作: rubular/r/qZOTsUikbo .注意:这与"日期"匹配，例如以及 9999-99-99 99:99:99 .如果这对您来说是个问题，则可以在找到潜在的字符串后对其进行验证.

See it in action here: rubular/r/qZOTsUikbo. Note: this matches "dates" like 9999-99-99 99:99:99 as well. If that is a problem for you, you could verify them after you found the potential Strings.

如果要解析它们，请使用SimpleDateFormat.

If you want to parse them, then use a SimpleDateFormat.

SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss"); Date date = sdf.parse("2013-12-24 18:31:20");