在python列表中找到最长的列表

本文介绍了在python列表中找到最长的列表的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我只是python的新手，我需要打印列表中包含最小和最大项目的列表.

I'm just a new in python and I need to print the lists which has minimum and maximum items in a list.

例如，如果我有:

total_list = [[1, 2, 3], [1, 2, 3, 4], [1,2,3,4,5]]

我需要返回一个列表，列表的长度应为最小和最大.我该如何简单地以python方式做到这一点?

I need to return a list with a minimum and maximum length of itself. How can I do it simply in python way?

我尝试对其进行迭代，但是我只能收到列表中每个项目的唯一len

I try to iterate over it but all I could receive is the only len of each item in a list

输出必须为:

total_list[0] and total_list[2]

预先感谢

推荐答案

max和min函数接受key参数，该参数将根据定义为键的值找到可迭代的最大值.所以，试试这个:

max and min function in python accepts a key argument that will find the max of an iterable based on what defined as a key. so, try this:

max(total_list, key=len)

然后您可以使用total_list.index查找那些索引

then you can use total_list.index to find those indexes