在递归函数中产生

本文介绍了在递归函数中产生的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我正在尝试对给定路径下的所有文件执行某些操作。我不想事先收集所有文件名，然后用它们做一些事情，所以我尝试了这个：

I am trying to do something to all the files under a given path. I don't want to collect all the file names beforehand then do something with them, so I tried this:

import os import stat def explore(p): s = '' list = os.listdir(p) for a in list: path = p + '/' + a stat_info = os.lstat(path ) if stat.S_ISDIR(stat_info.st_mode): explore(path) else: yield path if __name__ == "__main__": for x in explore('.'): print '-->', x

但是这个代码在命中它们时跳过目录，而不是放弃它们的内容。我做错了什么？

But this code skips over directories when it hits them, instead of yielding their contents. What am I doing wrong?

推荐答案

使用 os.walk 而不是重新发明轮子。

Use os.walk instead of reinventing the wheel.

特别是，按照图书馆文档中的示例，这是一个未经测试的尝试：

In particular, following the examples in the library documentation, here is an untested attempt:

import os from os.path import join def hellothere(somepath): for root, dirs, files in os.walk(somepath): for curfile in files: yield join(root, curfile) # call and get full list of results: allfiles = [ x for x in hellothere("...") ] # iterate over results lazily: for x in hellothere("..."): print x