空置状态有什么意义?

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我想知道在不为变量设置新值的情况下调用setState的要点.

I want to know the point behind calling setState without setting a new value to the variables.

readLocal() async { prefs = await SharedPreferences.getInstance(); id = prefs.getString('id') ?? ''; if (id.hashCode <= peerId.hashCode) { groupChatId = '$id-$peerId'; } else { groupChatId = '$peerId-$id'; } setState(() {}); }

推荐答案

我会说这只是一个惯例.上面可以改写为

I would say it's just a convention. The above can be re-written as

readLocal() async { prefs = await SharedPreferences.getInstance(); setState(() { id = prefs.getString('id') ?? ''; if (id.hashCode <= peerId.hashCode) { groupChatId = '$id-$peerId'; } else { groupChatId = '$peerId-$id'; } }); }

两者都会做同样的事情.对state variable进行突变后再调用setState(() {})看起来很简洁而且很容易实现.

Both will do the same thing. Calling setState(() {}) after mutating the state variable looks neat and reabable.

根据setState的实现部分，将按顺序排列下面的内容.

As per the implementation section of setState, it will below things in order.

断言.如果任何断言失败，则引发异常并在那里停止.

执行回调函数(final dynamic result = fn() as dynamic;)

要求框架重建(_element.markNeedsBuild();)

Assertions. If any assert fails, throws exception and stops there.

Execute the callback function (final dynamic result = fn() as dynamic;)

Ask framework to rebuild(_element.markNeedsBuild();)