在不丢失堆栈跟踪的情况下重新抛出 Java 中的异常

本文介绍了在不丢失堆栈跟踪的情况下重新抛出 Java 中的异常的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

在 C# 中，我可以使用 throw; 语句重新引发异常，同时保留堆栈跟踪:

In C#, I can use the throw; statement to rethrow an exception while preserving the stack trace:

try { ... } catch (Exception e) { if (e is FooException) throw; }

Java 中是否有类似的东西(不会丢失原始堆栈跟踪)?

Is there something like this in Java (that doesn't lose the original stack trace)?

推荐答案

catch (WhateverException e) { throw e; }

将简单地重新抛出您捕获的异常(显然，周围的方法必须通过其签名等来允许这一点).异常将保留原始堆栈跟踪.

will simply rethrow the exception you've caught (obviously the surrounding method has to permit this via its signature etc.). The exception will maintain the original stack trace.