本文介绍了如何从命令输出的行创建数组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个名为failedfiles.txt的文件,其内容如下:
I have a file called failedfiles.txt with the following content:
failed1 failed2 failed3我需要使用grep返回该文件中每一行的内容,并将输出保存在要访问的列表中.所以我想要这样的东西:
I need to use grep to return the content on each line in that file, and save the output in a list to be accessed. So I want something like this:
temp_list=$(grep "[a-z]" failedfiles.txt)但是,这是我输入
echo ${temp_list[0]}我得到以下输出:
failed1 failed2 failed3但是我想要的是什么时候去做
But what I want is when I do:
echo ${temp_list[0]}要打印
failed1当我这样做时:
echo ${temp_list[1]}要打印
failed2谢谢.
推荐答案您未创建了数组.您所做的是命令替换,只需将将命令输出到变量.
You did not create an array. What you did was Command Substitution which would simply put the output of a command into a variable.
要创建数组,请说:
temp_list=( $(grep "[a-z]" failedfiles.txt) )您可能还想参考关于阵列的指南.
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如何从命令输出的行创建数组
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