PHP：显示目录中最新的图像？

本文介绍了PHP：显示目录中最新的图像？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有一台摄像机服务器将图像传输到网络服务器。任何人都可以提出我需要通过服务器的公共根目录（/ public_html）并显示四个最新图像的PHP代码段？

I have a camera server FTPing images to a webserver. Can anyone suggest the PHP snippet I'd need that would look through the server's public root directory (/public_html) and display the four most recent images?

我可以告诉相机服务器以日期/时间命名上传的图像，但是需要[例如。 image-021020102355.jpg 为2010年10月2日下午11:55创建的图像

I can tell the camera server to name uploaded images by date/time, however needed [eg. image-021020102355.jpg for an image created 2nd oct 2010 at 11:55pm]

谢谢！

推荐答案

这应该做到这一点：

This should do it:

<?php foreach (glob('*.jpg') as $f) { # store the image name with the last modification time and imagename as a key $list[filemtime($f) . '-' . $f] = $f; } $keys = array_keys($list); sort($keys); # sort is oldest to newest, echo $list[array_pop($keys)]; # Newest echo $list[array_pop($keys)]; # 2nd newest

如果您可以创建文件名YYYYMMDDHHMM.jpg sort（）可以将它们放在右边订单，这将工作：

If you can make the filenames YYYYMMDDHHMM.jpg sort() can put them in the right order and this would work:

<?php foreach (glob('*.jpg') as $f) { # store the image name $list[] = $f; } sort($list); # sort is oldest to newest, echo array_pop($list); # Newest echo array_pop($list); # 2nd newest