PHP使用GET方法

本文介绍了PHP使用GET方法的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

< form action =addScript.phpmethot =POSTenctype =多部分/格式数据> < tr> < td>产品标题：< / td>< td>< input type =textname =titleid =title/>< / td> < / tr> < tr> < td>产品描述：< / td>< td>< textarea rows =5cols =40name =descriptionid =description>< / textarea> < / TD> < / tr> < tr> < td>价格（USD $）：< / td>< td>< input type =textname =priceid =price/>< / td> < / tr> < tr> < td>个人资料图片：< / td>< td>< input type =filename =profilepicid =profilepic/>< / td> < / tr> < tr> < td>其他图片：< / td>< td> < div id =picturesstyle =border：1px solid black;>< table> < tr>< td> 1< / td>< td>< input type =fileid =pic1name =pic1/>< / td> TR> < tr>< td> 2< / td>< td>< input type =fileid =pic2name =pic2/>< / td> TR> tr< td> 3< td>< td>< input type =fileid =pic3name =pic3/>< / td>< TR> < / table> < / div> < / td> < / tr> < tr> < td>< / td>< td>< input type =submitvalue =Add/>< / td> < / form>

问题是，即使我使用方法POST，当它调用addScript.php时，使用的方法实际上是GET，我的链接是 www.domain/addScript.php?name= ..& description = ... etc。 如果我在php文件中使用 $ name = $ _ REQUEST ['title']; ，我得到这个错误：未定义的索引：title / home / domain /public_html/addScript.php on line 13 。我该如何解决这个问题？

编辑 这是我的PHP没有mysqli_connect（）;

$ b $

$ name = $ _ POST ['title']; $ description = $ _ POST ['description']; $ price = $ _ POST ['price']; $ profilePic = $ _ FILES ['profilepic'] ['name']; $ path =images /; //在图片/文件夹中移动图片并获得它们的路径 $ pic1 = $ _ FILES ['pic1'] ['name']; $ pictmp = $ _ FILES ['pic1'] ['tmp_name']; $ moveResult = move_uploaded_file（$ pictmp，$ path）; $ pic2 = $ _ FILES ['pic2'] ['name']; $ pictmp = $ _ FILES ['pic2'] ['tmp_name']; $ moveResult = move_uploaded_file（$ pictmp，$ path）; $ pic3 = $ _ FILES ['pic3'] ['name']; $ pictmp = $ _ FILES ['pic3'] ['tmp_name']; $ moveResult = move_uploaded_file（$ pictmp，$ path）; $ pic1Path = $ path。$ pic1; $ pic2Path = $ path。$ pic2; $ pic3Path = $ path。$ pic3; //在数据库中插入信息 $ sql =INSERT INTO产品（名称，说明，价格，profile_pic，pic1，pic2，pic3） VALUES '$名'， '$说明'， '$价格'，$ profilePic， '$ pic1Path'， '$ pic2Path'， '$ pic3Path'）; if（！mysqli_query（$ con，$ sql））{ die（ERROR.mysqli_error（$ con））; }

我总是收到这个错误

错误您的SQL语法错误;请检查第3行 重新编辑：

现在我可以看到回复的确认，但它填充我的error_log这些错误，并在数据库中的列大多是空的。

[05-Feb-2014 15:01 ：12 UTC] PHP注意：未定义的索引：在第13行的/home/domain/public_html/addScript.php中的标题 [05-Feb-2014 15:01:12 UTC] PHP Notice：Undefined index：description in /home/domain/public_html/addScript.php on line 14 [05-Feb-2014 15:01:12 UTC] PHP注意：Undefined index：price in /home/domain/public_html/addScript.php on line 15 [05-Feb-2014 15:01:12 UTC] PHP注意：未定义的索引：profilepic in /home/domain/public_html/addScript.php on line 16 [05-Feb-2014 15 ：01：12 UTC] PHP注意：未定义索引：pic1在/home/domain/public_html/addScript.php在线20 [05-Feb-2014 15:01:12 UTC] PHP注意：未定义的索引：pic1 in /home/domain/public_html/addScript.php on line 21 [05-Feb-2014 15 PHP的注意：未定义的索引：pic2在/home/domain/public_html/addScript.php在线24 [05-Feb-2014 15:01:12 UTC] PHP公告：未定义索引：图2在/home/domain/public_html/addScript.php 25行 [05-Feb-2014 15:01:12 UTC] PHP注意：未定义索引：pic3在/home/domain/public_html/addScript.php在线28 [05-Feb-2014 15:01:12 UTC] PHP注意：未定义的索引：pic3在/home/domain/public_html/addScript.php上线29

重新编辑

code> var_dump（$ _ REQUEST）; 在$ name之前的PHP文件中，并得到这个

array（7）{[name] =>字符串（4）aaaa[description] =>字符串（7）aaaaaaa[price] =>字符串（3）555[profilepic] =>字符串（7）cr7.jpg[pic1] =>字符串（9）copac.jpg[pic2] => string（9）close.png[pic3] =>字符串（12）obiectiv.jpg} 1产品增加了

但是DB中的列仍为空。

解决方案

您的表单中有错字。您键入 methot 而不是方法：

< form action =addScript.phpmethot =POSTenctype =multipart / form-data>

应该是 < form action =addScript.phpmethod =POSTenctype =multipart / form-data>

更新 （'$ name'，'$ description'，'$价格'，$ profilePic'，'$ pic1Path'，'$ pic2Path'，'$ pic3Path'）; ^^^^^ 这里

应该是 （'$ name'，' $说明， '$价格'， '$ profilePic'， '$ pic1Path'， '$ pic2Path'， '$ pic3Path'）; ^^^^^ 这里

I have this form :

<form action="addScript.php" methot="POST" enctype="multipart/form-data"> <tr> <td>Produt title : </td><td><input type="text" name="title" id="title" /></td> </tr> <tr> <td>Product description : </td><td><textarea rows="5" cols="40" name="description" id="description"></textarea></td> </tr> <tr> <td>Price (USD $) : </td><td><input type="text" name="price" id="price" /></td> </tr> <tr> <td>Profile Picture : </td><td><input type="file" name="profilepic" id="profilepic" /></td> </tr> <tr> <td>Other pictures : </td><td> <div id="pictures" style="border:1px solid black;"><table> <tr><td>1</td><td><input type="file" id="pic1" name="pic1" /></td></tr> <tr><td>2</td><td><input type="file" id="pic2" name="pic2" /></td></tr> <tr><td>3</td><td><input type="file" id="pic3" name="pic3" /></td></tr> </table> </div> </td> </tr> <tr> <td></td><td><input type="submit" value="Add" /></td> </form>

The problem is that even if I use method POST, when it calls addScript.php, the method used is actually GET and my link is www.domain/addScript.php?name=..&description=... etc. And if I use $name=$_REQUEST['title']; in the php file , I get this error :Undefined index: title in /home/domain/public_html/addScript.php on line 13.How can I solution this?

EDIT This is my PHP without the mysqli_connect();

$name=$_POST['title']; $description=$_POST['description']; $price=$_POST['price']; $profilePic=$_FILES['profilepic']['name']; $path="images/"; //move picures in images/ folder and get their path $pic1=$_FILES['pic1']['name']; $pictmp=$_FILES['pic1']['tmp_name']; $moveResult=move_uploaded_file($pictmp, $path); $pic2=$_FILES['pic2']['name']; $pictmp=$_FILES['pic2']['tmp_name']; $moveResult=move_uploaded_file($pictmp, $path); $pic3=$_FILES['pic3']['name']; $pictmp=$_FILES['pic3']['tmp_name']; $moveResult=move_uploaded_file($pictmp, $path); $pic1Path=$path.$pic1; $pic2Path=$path.$pic2; $pic3Path=$path.$pic3; //insert info in database $sql="INSERT INTO products ( name, description, price, profile_pic, pic1, pic2, pic3) VALUES ('$name','$description','$price',$profilePic','$pic1Path','$pic2Path','$pic3Path')"; if(!mysqli_query($con,$sql)){ die("ERROR ".mysqli_error($con)); }

And I always get this error

ERROR You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'images/','images/','images/')' at line 3

Re-EDIT :

Now I can see the confirmation echoed, but it fills my error_log with these errors and the columns in the database are mostly empty .

[05-Feb-2014 15:01:12 UTC] PHP Notice: Undefined index: title in /home/domain/public_html/addScript.php on line 13 [05-Feb-2014 15:01:12 UTC] PHP Notice: Undefined index: description in /home/domain/public_html/addScript.php on line 14 [05-Feb-2014 15:01:12 UTC] PHP Notice: Undefined index: price in /home/domain/public_html/addScript.php on line 15 [05-Feb-2014 15:01:12 UTC] PHP Notice: Undefined index: profilepic in /home/domain/public_html/addScript.php on line 16 [05-Feb-2014 15:01:12 UTC] PHP Notice: Undefined index: pic1 in /home/domain/public_html/addScript.php on line 20 [05-Feb-2014 15:01:12 UTC] PHP Notice: Undefined index: pic1 in /home/domain/public_html/addScript.php on line 21 [05-Feb-2014 15:01:12 UTC] PHP Notice: Undefined index: pic2 in /home/domain/public_html/addScript.php on line 24 [05-Feb-2014 15:01:12 UTC] PHP Notice: Undefined index: pic2 in /home/domain/public_html/addScript.php on line 25 [05-Feb-2014 15:01:12 UTC] PHP Notice: Undefined index: pic3 in /home/domain/public_html/addScript.php on line 28 [05-Feb-2014 15:01:12 UTC] PHP Notice: Undefined index: pic3 in /home/domain/public_html/addScript.php on line 29

Re-Re-EDIT

I added var_dump($_REQUEST); in the PHP file before the $name and got this

array(7) { ["name"]=> string(4) "aaaa" ["description"]=> string(7) "aaaaaaa" ["price"]=> string(3) "555" ["profilepic"]=> string(7) "cr7.jpg" ["pic1"]=> string(9) "copac.jpg" ["pic2"]=> string(9) "close.png" ["pic3"]=> string(12) "obiectiv.jpg" } 1 product added

But still columns in DB are empty.

解决方案

You have a typo in your form. You typed methot instead of method:

<form action="addScript.php" methot="POST" enctype="multipart/form-data">

should be

<form action="addScript.php" method="POST" enctype="multipart/form-data">

update

You're missing a quote in your SQL query:

('$name','$description','$price',$profilePic','$pic1Path','$pic2Path','$pic3Path')"; ^^^^^ HERE

should be

('$name','$description','$price','$profilePic','$pic1Path','$pic2Path','$pic3Path')"; ^^^^^ HERE