本文介绍了jQuery使用变量隐藏/显示div的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我是jQuery的入门者.
I am a nOOb to jQuery.
我想在jQuery中使用变量来隐藏/显示div.
I want to use variables in jQuery to hide/show divs.
我到目前为止所拥有的是:
what I have so far is:
$(document).ready(function(){ $('#listMenu a').click(function () { var getPage = $(this).attr("id"); var getName = $(this).attr("name"); //console.log(getPage); //console.log(getName); $("#" & getName ).show(); }); });firebug控制台显示我正确拥有了var, 但接下来我会收到此错误:
firebug console shows that I have the vars correctly, but I get this error next:
this [H] .style未定义 [此错误中断](function(){var R =/((?:((?:([^()] +)... typeof K ==="string"?K:K +"px") }})})();
this[H].style is undefined [Break on this error] (function(){var R=/((?:((?:([^()]+)...typeof K==="string"?K:K+"px")}})})();
任何帮助,我们感激不尽. sjs
any help is appreciated. sjs
推荐答案我认为你想写
$("#" + getName ).show();&不是javascript中的运算符,但+是.
& is not an operator in javascript, but + is.
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jQuery使用变量隐藏/显示div
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