该代码用于更新用户登录的IP地址。当我打印$ sql字符串时,它似乎是正确的,IP地址是1886883852,但更新到mysql后,值为2149463110.我试过将mysql中的数据类型设置为INT(11)bigint(12),都是一样的。 如果我尝试将字符串写为
The code is used to update the IP address user logged in. When I print the $sql string, it seems it is correct, the IP address is 1886883852, but after updated to mysql, the value is 2149463110. I have tried to set the data type in mysql as INT(11) bigint(12), all the same. If I try to write a string as
UPDATE ddns SET LastIP=1886883852, LastUpdate=now() WHERE ID=1直接使用,不使用任何变量,它可以正常工作。
directly, without using any variable, it works correctly.
真的无法理解。有人可以帮忙吗?
Really cannot understand. Anybody can help?
//get dns function getIP(){ //check the current ip address registered //Test if it is a shared client if (!empty($_SERVER['HTTP_CLIENT_IP'])){ $ipaddr=$_SERVER['HTTP_CLIENT_IP']; //Is it a proxy address }elseif (!empty($_SERVER['HTTP_X_FORWARDED_FOR'])){ $ipaddr=$_SERVER['HTTP_X_FORWARDED_FOR']; }else{ $ipaddr=$_SERVER['REMOTE_ADDR']; } $ipaddr = ip2long($ipaddr); return $ipaddr; } $ipaddr = getIP(); $sql = "UPDATE ddns SET LastIP=$ipaddr, LastUpdate=now() WHERE ID=1"; echo $sql; **//here UPDATE ddns SET LastIP=1886883852, LastUpdate=now() WHERE ID=1** $result = mysqli_query($dbh,$sql) or die("Query failed:"); **//Here after updated, the value of ipaddr in database is 2149463110** if ($result) echo "Update ddns successfully"; else echo "faild to update ddns";推荐答案
最后我找到原因。当我使用 Chrome 访问和更新时,数据库将写入2149463110,当我使用 firefox或safari 时,结果将是1886883852. 有什么解释吗?
Finally I find the reason. When I use Chrome to visit and update, the database will write 2149463110, when I use firefox or safari, the result will be 1886883852. Any explanation?
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php mysql更新IP地址无法正常工作
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