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问题描述
您好!我在文件夹applications / core创建了自己的类,并将其命名为MY_Output.php
Hello! I created my own class at folder applications/core and named it MY_Output.php
class MY_Output extends CI_Output { function set_status_header($code = 200, $text = '') { set_status_header($code, $text); $this->last_set_status_code = $code; return $this; } function get_status_header() { return $this->last_set_status_code; } }
At folder controllers i created new controller Error.php: <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed'); class Error extends MY_Output { public function __construct() { parent::__construct(); } function error_404() { $this->load->view('404'); } } ?>
如何从类Error中访问(调用)类MY_Output的函数?
How i can get access (call) to functions of class MY_Output from class Error?
推荐答案code = 200, code = 200,
text = ' ') { set_status_header( text = '') { set_status_header(
code,
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