数组值的总计数

本文介绍了数组值的总计数的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

在这里，我接受用户的几个挂载点，并使用每个值来获取主机上的可用空间.

Here I'm accepting few mount points from the user and using each value to get space available on the host.

./user_input.ksh -string /m01,/m02,/m03 #!/bin/ksh STR=$2 function showMounts { echo "$STR" arr=($(tr ',' ' ' <<< "$STR")) printf "%s\n" "$(arr[@]}" for x in "${arr[@]}" do free_space=`df -h "$x" | grep -v "Avail" | awk '{print $4}'` echo "$x": free_space "$free_space" done #echo "$total_free_space" }

问题:

如果任何用户输入安装不可用，如何退出循环? 目前仅在日志中添加错误.

如何获取total_free_space(即free_space的总和)?

How can I exit for loop if any of the user input mount not avaialble? currently it only add error in the log.

How to get total_free_space (i.e. sum of free_space)?

推荐答案

如果您想保留代码，请进行测试(此处没有ksh).如果您不在乎，请阅读爱德华·莫顿的答案.

If you want to keep your code , test this (no ksh here). If you don't care, read Ed Morton's answer.

./user_input.ksh -string /m01,/m02,/m03 #!/bin/ksh STR=$2 function showMounts { echo "$STR" arr=($(tr ',' ' ' <<< "$STR")) printf "%s\n" "${arr[@]}" for x in "${arr[@]}"; do free_space=$(df -P "$x" | awk 'NR > 1 && !/Avail/{print $4}') echo "$x: free_space $free_space" ((total_free_space+=$free_space)) done echo "$((total_free_space/1024/1000))G" } showMounts

警告:

"${arr[@]}"

不是

"$(arr[@]}"