用Kotlin和Mockito模拟通用接口

val x = f(Mockito.mock(X::class.java) as X<Int>)

但这会生成未经检查的演员表"警告.

But that would generate an "unchecked cast" warning.

@Mock lateinit var x: X<Int>

但是我不想使用@Mock批注，因为我希望字段最终输入.

But I do not want to use the @Mock annotation because I like to have my fields final.

引入一个辅助函数，如mockito-kotlin库确实:

Introduce a helper function, as the mockito-kotlin library does:

inline fun <reified T : Any> mock(): T = Mockito.mock(T::class.java)!!

然后这样称呼它:

val x: X<Int> = mock()

但是我不想使用辅助函数.

But I do not want to use helper functions.

是否存在一种优雅的纯Kotlin方法来模拟Mockito的通用接口? (我希望版本1.不带警告.)

Is there an elegant pure Kotlin way to mock a generic interface with Mockito? (I would prefer a version of 1. without the warning.)

只需使用 mockito-kotlin 项目.该项目包含所有必须具备的模仿者助手.并且还支持Mockito 2.1.

Just use mockito-kotlin project. This project contains all must have helpers for mockito. And supports mockito 2.1 as well.

已更新.要处理不熟练的演员"，请使用修饰的类型参数.

Upd. To deal with "uncheked cast" use Reified type parameters.

您说的是但是我不想使用辅助函数."但是为什么呢?这是内联函数，因此在编译时将在所有调用站点上内联.

You say that "But I do not want to use helper functions.", but why? This is inline function, so in compile time function will be inlined at all call sites will.