memcpy是否不会引发异常?

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希望这是一个简单的答案，因为这似乎是一个简单的问题，但是我无法在互联网上找到任何与此有关的信息.

Hopefully there is a simple answer to this as it seems a simple question, however I have not been able to find any information on this on the interwebs.

在以下代码段中，Visual Studio抱怨删除字节；"行上无法访问的代码.

In the following code snippet, Visual Studio complains of unreachable code at the line "delete bytes;"

try { memcpy(bytes, other.bytes, count); } catch (...) { delete[] bytes; throw; }

memcpy是否不会引发异常?

Does memcpy not throw exceptions?

推荐答案

否. memcpy是C函数.它不了解诸如异常之类的C ++功能. (当然，在C ++中使用它是完全合法的，尽管可以说不是最好的主意.)

No. memcpy is a C function. It doesn't know about C++ features such as exceptions. (Of course, it's perfectly legal to use it in C++, although arguably not the best idea).

响应karlphillip:我确实必须澄清我的想法:在C ++中，memcpy应该仅用于对象私有实现内的低级缓冲区副本.不应像在C语言中那样平凡地使用它(例如，复制数字数组)，因为普通香草缓冲区现在通常隐藏在类实现中.包装数组或其他大量数据的类(例如std :: array)公开用于操作其内容的方法.在我写这篇文章时，马克·兰瑟姆(Mark Ransom)很好地总结了它;-)

In response to karlphillip: I must indeed clarify my thoughts: in C++, memcpy should be used only for low-level buffer copies inside object private implementation. It shouldn't be used as mundanely as it was in C (for example to copy numbers arrays) because plain-vanilla buffers are now usually hidden inside class implementations. Classes that wrap arrays or other large amount of data (such as std::array) expose methods to manipulate their contents. And by the time I write this, Mark Ransom nicely summarized it ;-)