如何从当前位置找到最近的纬度和经度？

本文介绍了如何从当前位置找到最近的纬度和经度？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有一个字典，其中包含n个纬度，经度和地址的集合。我想计算哪个（纬度和纬度）点与ios中当前用户位置（纬度，纬度）最接近？

I have a dictionary with a collection of n number of latitude, longitude and address. I want to calculate which (latitude and langitude)point is closest from current user location(latitude ,langitude) in ios?

提前致谢

推荐答案

如果你想根据坐标计算，这里是一个简单的场景：只需要取出所有你的词典中的CLLocationCoordinate2D。

If you want to calculate based on the co-ordinates , here is simple scenario : Just take all of the "CLLocationCoordinate2D" from your dictionary .

例如：

MKPointAnnotation *annotaion=[MKPointAnnotaion alloc]alloc]; CLLocationCoordinate2D pointACoordinate = [annotation coordinate]; // If you have the co-ordinates in hand , then just make " CLLocation *loc2; " using Co-ordinates loc2 = [[CLLocation alloc] initWithLatitude:pointACoordinate.latitude longitude:pointACoordinate.longitude];

然后通过与使用此

then put loop or whichever you want to calculate the less distance by comparing with all using this

CLLocationDistance nearLocation=[ location distanceFromLocation:loc2]; // location --> your current Location

如果您想实现其他目的：那么只需按照秋刀鱼回答，他们很好地实现了。

If you want to achieve other than it : Then just follow saury answer, they are good to achieve perfectly.