例如，display 是一个用来将R作为newby来使用的东西， c $ c> 0.12345 为 12.345％。对此我有一些解决方法，但是这些都不是友好的。例如：
set.seed（1）m < - runif（5） paste（round（100 * m，2），％，sep =） [1]26.55％37.21％57.29％90.82％20.17％ sprintf（％1.2f %%，100 * m） [1]26.55％37.21％57.29％90.82％20.17％问题：是否有一个基本的R函数可以做到这一点？另外，是否有一个广泛使用的包提供了一个方便的包装？
尽管在？format ，？formatC 和？prettyNum ，我还没有找到一个适当方便的包装在基础R. ??percent没有产生任何有用的东西。 库（SOS）; findFn（格式百分比）返回1250个匹配 - 所以再次没用。 ggplot2 有一个函数 percent ，但是这不能控制舍入的准确性。
这几天有一个解决方案在 中 project/web/packages/scales/index.html> scale 包，如krlmlr的答案中所述。使用它，而不是我的手滚解决方案。
试试像
percent < - function（x，digits = 2，format =f，...）{ paste0（formatC（100 * x，format =格式，数字=数字，...），％）}例如，
x <-c（-1,0,0.1,0.555555,1,100）％（x）（如果您愿意，请将格式从 f到g。）
One of the things that used to perplex me as a newby to R was how to format a number as a percentage for printing.
For example, display 0.12345 as 12.345%. I have a number of workarounds for this, but none of these seem to be "newby friendly". For example:
set.seed(1) m <- runif(5) paste(round(100*m, 2), "%", sep="") [1] "26.55%" "37.21%" "57.29%" "90.82%" "20.17%" sprintf("%1.2f%%", 100*m) [1] "26.55%" "37.21%" "57.29%" "90.82%" "20.17%"Question: Is there a base R function to do this? Alternatively, is there a widely used package that provides a convenient wrapper?
Despite searching for something like this in ?format, ?formatC and ?prettyNum, I have yet to find a suitably convenient wrapper in base R. ??"percent" didn't yield anything useful. library(sos); findFn("format percent") returns 1250 hits - so again not useful. ggplot2 has a function percent but this gives no control over rounding accuracy.
解决方案An update, several years later:
These days there is a percent function in the scales package, as documented in krlmlr's answer. Use that instead of my hand-rolled solution.
Try something like
percent <- function(x, digits = 2, format = "f", ...) { paste0(formatC(100 * x, format = format, digits = digits, ...), "%") }With usage, e.g.,
x <- c(-1, 0, 0.1, 0.555555, 1, 100) percent(x)(If you prefer, change the format from "f" to "g".)
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