创建通用基础适配器?

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本文介绍了创建通用基础适配器?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧! 问题描述

我对创建一个通用BaseAdapter感兴趣,该适配器将应用于具有任何list_item的任何ListView.并将设置list_view的item_row.

I am interested in creating a generic BaseAdapter which will apply to any ListView having any list_item . And it will set the item_row for the list_view.

public class GenericAdapter extends BaseAdapter { Context context; ArrayList<HashMap<String, String>> list; LayoutInflater inflater; public GenericAdapter (Context context, ArrayList<HashMap<String, String>> list) { this.context = context; this.list = list; inflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE); } @Override public int getCount() { return list.size(); } @Override public Object getItem(int position) { return list.get(position); } @Override public long getItemId(int position) { return position; } @Override public View getView(int position, View convertView, ViewGroup parent) { View view = convertView; if(view == null) { view = inflater.inflate(R.layout.item_of_any_list, parent, false); // i have to do something here like there may be a method which must be call } /*HashMap<String, String> map = list.get(position); TextView textViewName = (TextView) view.findViewById(R.id.name); TextView textViewDate = (TextView) view.findViewById(R.id.date); //TextView textViewDesc = (TextView) view.findViewById(R.id.desc); textViewName.setText(map.get("name")); textViewDate.setText(map.get("date")); //textViewDesc.setText(map.get("description")); */ return view; }

我认为我必须创建一个获取接口并为单个项目设置item_row.但是我不知道这是有可能的.有人可以告诉我我如何实现它.

I think i have to create an interface that's get and set the item_row for individual item. But i don't know it may be possible . Can someone tell me how i can achieve it.

我的想法是创建一个接口,GenericAdapter实现该接口.在该界面中,有一种获取和设置item_row的方法.任何扩展GenericAdapter的类都必须实现该方法.这将帮助我们制造一个通用适配器.

My idea is to create an interface and GenericAdapter implements that interface. In that interface there is a method to get and set the item_row. Any class which extends GenericAdapter must implement that method. it will help us make a generic adapter.

当我们扩展该适配器时,我们不需要编写所有代码,例如getCount,getItem,getItemId,我们只需要重写一个inflateLayout函数即可.必须在getView内

When we extend that adapter we don't need to write all code like getCount, getItem,getItemId, we just have to override a function which is to inflateLayout. which must be inside getView

预先感谢

推荐答案

两年后回答我自己的问题.

要制作通用适配器,您需要parent class中的abstract方法,该方法应由child实施.因此,GenericAdapter必须为Abstract,并为要更改的数据创建abstract方法.

In order to make Generic Adapter you need abstract methods in parent class which should be implemented by child. So GenericAdapter must be Abstract and create abstract methods for data you want to change.

我有不同类型的 ArrayList 要显示在适配器中,只是model class是不同的.所以我决定写一个genericAdapter.如果某人interested用于列表视图,则这用于recyclerview.让我知道.

I have different types of ArrayList to show in Adapter only it's model class is different. So I decided to write a genericAdapter. This is for recyclerview if someOne interested for listview. Let me know.

GenericAdapter

public abstract class GenericAdapter<T> extends RecyclerView.Adapter<RecyclerView.ViewHolder> { private Context context; private ArrayList<T> items; public abstract RecyclerView.ViewHolder setViewHolder(ViewGroup parent); public abstract void onBindData(RecyclerView.ViewHolder holder, T val); public GenericAdapter(Context context, ArrayList<T> items){ this.context = context; this.items = items; } @Override public RecyclerView.ViewHolder onCreateViewHolder(ViewGroup parent, int viewType) { RecyclerView.ViewHolder holder = setViewHolder(parent); return holder; } @Override public void onBindViewHolder(RecyclerView.ViewHolder holder, int position) { onBindData(holder,items.get(position)); } @Override public int getItemCount() { return items.size(); } public void addItems( ArrayList<T> savedCardItemz){ items = savedCardItemz; this.notifyDataSetChanged(); } public T getItem(int position){ return items.get(position); } }

我像

adapter = new GenericAdapter<DataModel>(context,modelList) { @Override public RecyclerView.ViewHolder setViewHolder(ViewGroup parent) { final View view = LayoutInflater.from(context).inflate(R.layout.item_view_holder, parent, false); ItemViewHolder viewHolder = new ItemViewHolder(context, view); return viewHolder; } @Override public void onBindData(RecyclerView.ViewHolder holder1, DataModel val) { DataModel userModel = val; ItemViewHolder holder = (ItemViewHolder)holder1; holder.name.setText(userModel.getName()); holder.fatherName.setText(userModel.getFatherName()); } }; mRecyclerView.setAdapter(adapter);

具有搜索排序功能的RecyclerView

RecyclerView with Search sort functionality

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创建通用基础适配器?

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