本文介绍了旋转 SCNNode 相对本地坐标的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我试图通过 SCNAction 旋转一个节点,但它相对于父节点的坐标空间旋转.是否可以相对于本地坐标系旋转节点?
解决方案好的.您可以使用 convertVector 方法获取旋转轴的父空间坐标.>
例如,此动作将围绕局部 x 轴旋转 180 度:
SCNAction.rotate(by: .pi, around: node.convertVector(SCNVector3(1, 0, 0), to: node.parent), duration: TimeInterval(5))I'm trying to rotate a node by SCNAction, but it rotates relative to parent’s coordinate space. Is it possible to rotate a node relative local's coordinate system?
解决方案Sure. You can obtain parent's space coordinates for rotation axis with convertVector method.
For example, this action will do 180 degrees rotation around local x-axis:
SCNAction.rotate(by: .pi, around: node.convertVector(SCNVector3(1, 0, 0), to: node.parent), duration: TimeInterval(5))
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