使用rle c ++解压缩文件

本文介绍了使用rle c ++解压缩文件的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

// RLE algorithm.cpp : Defines the entry point for the console application. // #include "stdafx.h"//work with txt files only #include"iostream" #include "fstream" using namespace std; ///////// structures ////////////// void decompress(char* data, int count, FILE* outfile); char* readFileData(char* filename, int* count_ptr); struct compress { char runValue; int counter; compress(int x=0,int y=1):runValue(x),counter(y){}//constructor }; int _tmain(int argc, _TCHAR* argv[]) { fstream infile1,infile2,outfile; struct compress zip; char cur; char next; char fName[100]=""; cout<<"please enter file name :"; cin>>fName; infile1.open(fName,ios::in); infile1.unsetf(ios::skipws); infile2.open(fName,ios::in); infile2.unsetf(ios::skipws); outfile.open("compressed.txt",ios::out); outfile.unsetf(ios::skipws); while(1) { infile1>>cur; if(infile1.fail()) break; infile2>>next; infile2>>next; if(infile2.fail()) break; while(1) { if(cur!=next) { outfile<<"1"<<cur; // handled error infile1>>cur; infile2>>next; if(infile2.fail()) break; } if(cur==next) { while(cur==next) { zip.counter++; infile1>>cur; infile2>>next; if(infile2.fail()) break; } zip.runValue=cur; outfile<<zip.counter<<zip.runValue; zip.counter=1; infile1>>cur; infile2>>next; if(infile2.fail()) break; } }// end of first while }// end of file infile1.close(); infile2.close(); outfile.close(); cout<<"compression operion completed.\n"; return 0; } void decompress(char* data, int count, FILE* outfile) { // TODO: decompress the data instead of just writing it out to the file for (int i = 0; i<count;> { putc(data[i], outfile); // write out a single byte of data } } char* readFileData(char* filename, int* count_ptr) { // Returns a pointer to an array storing the file data. // Sets the variable pointed to by 'count' to contain the file size. // Exits the program if the filename doesn't exist. FILE* infile = fopen(filename, "rb.txt"); if (!infile) { printf("No such file \"%s\"!\n", filename); exit(1); } // Get file size by going to the end of the file, getting the // position, and then going back to the start of the file. fseek(infile, 0, SEEK_END); int count = ftell(infile); fseek(infile, 0, SEEK_SET); // read the data from the file char* data = new char[count]; fread(data, 1, count, infile); fclose(infile); *count_ptr = count; return data; }

这是代码，我需要将其解压缩

this is the code and i need to decompress it

推荐答案

算法创建一个包含4字节计数器后跟字符的记录的压缩文件。 文件看起来像这样 - iiiic iiiic iiiic iiiic iiic 要解压缩文件，请在5个字节处读取压缩文件一段时间，即读取 iiiic 。 将字符c写入输出文件iiii次。 循环执行此操作直至结束该文件。 The algorithm creates a compressed file containing records with a 4 byte counter followed by the character. The file would look something like this - iiiiciiiiciiiiciiiiciiic To decompress the file read the compressed file 5 bytes at a time, ie, read iiiic. Write the character c to the output file iiii times. Do this in a loop till the end of the file.