我想一个字符串分割成令牌,但有些递归。我试图解析:
I'm trying to split a string into tokens but somewhat recursively. I am trying to parse:
"content=0&website=Google"让我有办法拿出的参数和值。如果我尝试 strtok的我最终摧毁我要解析两次字符串。所以,我想
so that I have a way to take out the parameters and values. If I try strtok I end up destroying the string I want to parse twice. So I tried
char *contents = "content=0&website=Google" char arg[100]; char value[100]; sscanf(contents, "%s&%s", arg, value);作为第一关,希望能解析 ARG 了,但失败了,而 ARG 包含整个字符串。我试着用%S \\&放大器;%的想着&安培; 是一个保留字,但没有运气
as a first pass, hoping to parse arg again, but it fails, and arg contains the entire string. I tried using "%s\&%s" thinking & was a reserved word, but no luck there.
帮助!
编辑:
这是我的strtok黑客:
This was my strtok hack:
static void readParams(char * string, char * param, char * value) { printf("This is the string %s\n",string); char * splitted = strtok (string,"="); while (splitted != NULL) { printf("This is the string %s\n",splitted); splitted = strtok (NULL, "="); // Then do some saving to param and value } } char * splitted = strtok (contents,"&"); int counter = 0; while (splitted != NULL) { char * t_str = strdup(splitted); readParams(t_str, param, value); splitted = strtok (NULL, "&"); }但它不工作,因为分裂的 strtok的末成为gobbldygook。
but it doesn't work because splitted's strtok at the end becomes gobbldygook.
推荐答案下面是一个似乎工作的解决方案:
Here is a solution that seems to work:
char *contents = "content=0&website=Google"; char arg[100] = {0}; char value[100] = {0}; sscanf(contents, "%[^&]&%s", arg, value); printf("%s\n%s\n", arg, value);更多推荐
拆分C字符串到使用sscanf的令牌
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