拆分C​​字符串到使用sscanf的令牌

本文介绍了拆分C​​字符串到使用sscanf的令牌的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我想一个字符串分割成令牌，但有些递归。我试图解析：

I'm trying to split a string into tokens but somewhat recursively. I am trying to parse:

"content=0&website=Google"

让我有办法拿出的参数和值。如果我尝试 strtok的我最终摧毁我要解​​析两次字符串。所以，我想

so that I have a way to take out the parameters and values. If I try strtok I end up destroying the string I want to parse twice. So I tried

char *contents = "content=0&website=Google" char arg[100]; char value[100]; sscanf(contents, "%s&%s", arg, value);

作为第一关，希望能解析 ARG 了，但失败了，而 ARG 包含整个字符串。我试着用％S \\＆放大器;％的想着＆安培; 是一个保留字，但没有运气

as a first pass, hoping to parse arg again, but it fails, and arg contains the entire string. I tried using "%s\&%s" thinking & was a reserved word, but no luck there.

帮助！

编辑：

这是我的strtok黑客：

This was my strtok hack:

static void readParams(char * string, char * param, char * value) { printf("This is the string %s\n",string); char * splitted = strtok (string,"="); while (splitted != NULL) { printf("This is the string %s\n",splitted); splitted = strtok (NULL, "="); // Then do some saving to param and value } } char * splitted = strtok (contents,"&"); int counter = 0; while (splitted != NULL) { char * t_str = strdup(splitted); readParams(t_str, param, value); splitted = strtok (NULL, "&"); }

但它不工作，因为分裂的 strtok的末成为gobbldygook。

but it doesn't work because splitted's strtok at the end becomes gobbldygook.

推荐答案

下面是一个似乎工作的解决方案：

Here is a solution that seems to work:

char *contents = "content=0&website=Google"; char arg[100] = {0}; char value[100] = {0}; sscanf(contents, "%[^&]&%s", arg, value); printf("%s\n%s\n", arg, value);