如何使用另一个函数从列表中获取点值

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所以我不确定该如何解决这个问题，但是据我了解，我想使用另一个函数从52个数字的列表中获取点，然后我想返回一个包含以下内容的列表:列表中不同整数的点之和.

So I am not sure how I am to go about doing this problem, but from my understanding I am suppose to use another function to get points from a list of 52 numbers and then I am suppose to return a list that contains the sum of the points from the different integers from the list.

问题要问:

编写一个函数，该函数将1到1之间的自然数列表作为参数 52(含)，并使用练习题3"返回包含以下各项的所有可能总和的列表 与列表中的数字相对应的所有卡的点值.

write a function that takes, as an argument, a list of natural numbers between 1 and 52, inclusive, and uses Practice Problem 3 to return a list containing all of the distinct possible sums of the point values of all of the cards corresponding to the numbers in the list.

因此，从练习3开始，将点值分配给52个整数列表. 代码是:

So to start practice problem 3 assigns point values to a list of 52 integers. It's code:

def getPoints(n): n = (n-1) % 13 + 1 if n == 1: return [1,11] if 2 <= n <= 10: return [n] if 11 <= n <= 13: return [10]

现在，我要使用函数3来创建一个新函数，以获取我从52个数字中选择的数字列表中的点.

Now I am to make a new function utilizing function 3 to obtain points for a list of numbers I choose from the 52 numbers.

这是新功能的代码:

def getPointTotal(aList): for i in aList: points = getPoints(i) return aList, points

它不完整，因为我被卡住了.现在就坐了.

It isn't complete because I am stuck. Right now as it sits I get.

>>>getPointTotal([10, 1]) >>>[12, 1], [10] # 12 is worth 10 points

所以我注意到它只是从52个数字的列表中取出一个整数，但我不知道如何从列表中获得多个整数.

So I noticed it was only taking one integer from the list of 52 numbers, but I don't know how to make to get more than one of the integers from the list.

我尝试将返回值移动到循环内，但随后它给了我:

I've tried moving the return inside the loop but then it gives me:

>>>getPointTotal([8, 11]) >>>[8, 11], [10] #11 is worth 10 points

如何使被调用函数遍历多个项目?

How do I get the called function to go over more than one item?

推荐答案

您需要附加循环内部的结果，而不要覆盖:

you need to append the results of the inside of your loop, not overwrite:

def getPointTotal(aList): points = [] for i in aList: points += getPoints(i) return aList, points