本文介绍了PHP从JSON编码获取值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个url传递参数,使用json_encode每个值,如下所示:
I have an url passing parameters use json_encode each values like follow:
$json = array ( 'countryId' => $_GET['CountryId'], 'productId' => $_GET['ProductId'], 'status' => $_GET['ProductId'], 'opId' => $_GET['OpId'] ); echo json_encode($json);返回的结果为:
{ "countryId":"84", "productId":"1", "status":"0", "opId":"134" }我可以使用json_decode解析每个值以进行进一步的数据处理吗?
Can I use json_decode to parse each values for further data processing?
谢谢.
推荐答案json_decode()如果第二个值是true,则将返回对象或数组:
json_decode() will return an object or array if second value it's true:
$json = '{"countryId":"84","productId":"1","status":"0","opId":"134"}'; $json = json_decode($json, true); echo $json['countryId']; echo $json['productId']; echo $json['status']; echo $json['opId'];更多推荐
PHP从JSON编码获取值
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