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问题描述
我创建了以下方法以创建唯一的随机数。 (此唯一值属于树的节点):
I have created the following method so as to create unique random numbers . (This unique values belong to the nodes of a tree):
static Random rand = new Random(); public static ArrayList<Node> go(int n) { ArrayList<Node> list = new ArrayList<Node>(); ArrayList<Integer> numList = new ArrayList<Integer>(); // TODO Auto-generated method stub for(int i = 1; i<=5; i++) { int number = rand.nextInt(10)+1; if(list.size()>0 && !check(list,number)) { i--; continue; } numList.add(number); Node node = new Node(); node.data = number; list.add(node); } int w = 0; for (Node d : list) { System.out.println(w+": "+d.data); w++; } return list; } private static boolean check(ArrayList<Node> list, int num) { // TODO Auto-generated method stub boolean b = false; /*if(list.size()==0) return true; */ for (Node node : list) { if(node.data == num) b = false; else b = true; } return b; }但它不会创建唯一的数字,我的列表中仍然有重复数字。喜欢:
But it doesn’t create unique numbers and there are still duplicates in my list. Like :
0: 10 1: 1 2: 10 3: 5 4: 6推荐答案
问题在于如果找到重复的数字,你不会在check函数内停止for循环。循环继续,b可以变回true。
The problem is that you don't stop the for loop inside the check function if it finds a duplicated number. The loop continues and b can change back to true.
你应该做的是例如:
private static boolean check(ArrayList<Node> list, int num) { for (Node node : list) { if(node.data == num) return false; } return true; }更多推荐
创建唯一的随机数
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