如何生成两个不同的随机数？

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我需要生成两个不同的随机数，它们不能彼此相等或与第三个数相等。我尝试使用很多if来涵盖所有可能性，但似乎我的算法技能不是那么好。

I need to generate two different random numbers, they can't be equal to each other or to a third number. I tried to use a lot of if's to cover every possibility but, it seems my algorithm skills are not that good.

任何人都可以帮我吗？

var numberOne = Math.floor(Math.random() * 4); var numberTwo = Math.floor(Math.random() * 4); var numberThree = 3; // This number will not always be 3 if((numberOne == numberThree) && (numberOne + 1 < 3)) { numberOne++; } else if ((numberOne == numberThree) && (numberOne + 1 == 3)) { numberOne = 0; } if ((numberOne == numberTwo) && (numberOne+1 < 3)) { if (numberOne+1 < 3) { numberOne++; } else if(numberThree != 0) { numberOne = 0; } }

这是我到目前为止，下一步将是：

This is what I have so far, the next step would be:

if (numberTwo == numberThree) { (...) }

我的思路是否合适？ 注意：生成的数字需要在0到3之间。提前感谢。

Is my line of thought right? Note: Numbers generated need to be between 0 and 3. Thanks in advance.

推荐答案

你可以运行一个 while 循环，直到所有数字都不同。

You can run a while loop until all numbers are different.

// All numbers are equal var numberOne = 3; var numberTwo = 3; var numberThree = 3; // run this loop until numberOne is different than numberThree do { numberOne = Math.floor(Math.random() * 4); } while(numberOne === numberThree); // run this loop until numberTwo is different than numberThree and numberOne do { numberTwo = Math.floor(Math.random() * 4); } while(numberTwo === numberThree || numberTwo === numberOne);

这是基于@jfriend00建议的上述代码的jsfiddle jsfiddle/x4g4kkwc/1 。

Here is the jsfiddle with the above code based on @jfriend00's suggestion jsfiddle/x4g4kkwc/1.

以下是原始工作演示： http：// jsfiddle。 net / x4g4kkwc /

Here is the original working demo: jsfiddle/x4g4kkwc/