Groovy:将数组转换为JSon

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本文介绍了Groovy:将数组转换为JSon的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧! 问题描述

Groovy是新手,并且无法将数组转换为JSON。计算的JSON应该包含我的数组列表中的所有值,但它只存储最后一个值。这里是代码:

Am new to Groovy and am having trouble converting an array to JSON. The JSON computed should have all the values from my array list, but it is storing only the last one. Here is the code:

def arraylist = [["0",2],["1",8],["2",6],["3",8],["4",3]] def arraysize = arraylist.size() def builder = new groovy.json.JsonBuilder() builder ({ cols([ { "id" "hours" "label" "Hours" "type" "string" }, { "id" "visitor" "label" "Visitors" "type" "number" } ]) rows([ { for( i in 0..< arraysize ) { c([ { "v" arraylist[i][0] }, { "v" arraylist[i][1] } ]) }//for } ]) }) println builder.toPrettyString()

可以尝试在这里运行代码: groovyconsole.appspot/

Can try running the code here: groovyconsole.appspot/

预期输出在这里:

{ "cols": [ { "id": "hours", "label": "Hours", "type": "string" }, { "id": "visitor", "label": "Visitors", "type": "number" } ], "rows": [ { "c": [ { "v": "0" }, { "v": 2 } ] }, { "c": [ { "v": "1" }, { "v": 8 } ] }, { "c": [ { "v": "2" }, { "v": 6 } ] }, { "c": [ { "v": "3" }, { "v": 8 } ] }, { "c": [ { "v": "4" }, { "v": 3 } ] } ] }

推荐答案

类似这样的东西似乎给出了您想要的结果:

Something like this seems to give the result you wanted:

def arraylist = [["0",2],["1",8],["2",6],["3",8],["4",3]] def builder = new groovy.json.JsonBuilder() builder { cols( [ [ id: "hours", label: "Hours", type: "string" ], [ id: "visitor", label: "Visitors", type: "number" ] ] ) rows( arraylist.collect { pair -> [ c: pair.collect { item -> [ v: item ] } ] } ) } println builder.toPrettyString()

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Groovy:将数组转换为JSon

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本文标签:数组   转换为   Groovy   JSon

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