R中每小时间隔的汇总时间列

本文介绍了R中每小时间隔的汇总时间列的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我在R中有以下格式的df。以每小时的时间间隔为基础进行汇总的最简单方法是什么，当前是每分钟

I have a df in R in the following format. What could be the easiest way to aggregate this on an hourly time interval basis, currently it is every minute

theTime24 Amount 988 2015-02-04 23:53:00 2 989 2015-02-04 23:55:00 1 990 2015-02-04 23:56:00 3 991 2015-02-04 23:57:00 2 992 2015-02-04 23:58:00 1 993 2015-02-04 23:59:00 2

推荐答案

（由于回答的用户（@ user20650）将其添加为评论，所以我

(Since the user (@user20650) who answered added it as a comment, I am answering my own question)

aggregate(Amount ~ format(as.POSIXct(countByCountryTime$theTime24), "%Y-%m-%d %H"), data=countByCountryTime, sum)