我的问题很简单:
有什么方法可以通过bash命令的pythonic方式进行编码吗?
Is there any way to code in a pythonic way that bash command?
hexdump -e '2/1 "%02x"' file.dat很明显,没有使用os,popen或任何快捷方式;)
Obviously, without using os, popen, or any shortcut ;)
尽管我没有明确指定,但是如果代码在Python3.x中可以正常工作,那就太好了
although I've not explicitly specified, it would be great if the code was functional in Python3.x
谢谢!
推荐答案如果您只关心Python 2.x,请 line.encode('hex') 会将二进制数据块编码为十六进制.所以:
If you only care about Python 2.x, line.encode('hex') will encode a chunk of binary data into hex. So:
with open('file.dat', 'rb') as f: for chunk in iter(lambda: f.read(32), b''): print chunk.encode('hex')(默认情况下,IIRC,hexdump每行打印32对十六进制;如果没有,只需将32更改为16或其他内容……)
(IIRC, hexdump by default prints 32 pairs of hex per line; if not, just change that 32 to 16 or whatever it is…)
如果两个参数 iter 看起来莫名其妙,请单击帮助链接;一旦您有了主意,它就不会太复杂.
如果您关心Python 3.x,请 encode 仅适用于将Unicode字符串转换为字节的编解码器;任何以其他方式转换的编解码器(或任何其他组合),则必须使用 codecs.encode 明确地做到这一点:
If you care about Python 3.x, encode only works for codecs that convert Unicode strings to bytes; any codecs that convert the other way around (or any other combination), you have to use codecs.encode to do it explicitly:
with open('file.dat', 'rb') as f: for chunk in iter(lambda: f.read(32), b''): print(codecs.encode(chunk, 'hex'))或者最好使用 hexlify :
Or it may be better to use hexlify:
with open('file.dat', 'rb') as f: for chunk in iter(lambda: f.read(32), b''): print(binascii.hexlify(chunk))如果您除了打印输出外还想做些其他事情,而不是将整个文件读入内存,您可能想要创建一个迭代器.您可以将其放在函数中,然后将print更改为yield,该函数将恰好返回您想要的迭代器.或使用genexpr或map呼叫:
If you want to do something besides print them out, rather than read the whole file into memory, you probably want to make an iterator. You could just put this in a function and change that print to a yield, and that function returns exactly the iterator you want. Or use a genexpr or map call:
with open('file.dat', 'rb') as f: chunks = iter(lambda: f.read(32), b'') hexlines = map(binascii.hexlify, chunks)更多推荐
十六进制转储文件的pythonic方法
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