我正在尝试编写一个查询来查找用户游戏的得分排名.我需要它接收用户 ID,然后将该用户的相对排名返回到其他用户的分数.有一个用户和一个游戏桌.游戏表具有一对多关系的 userId 字段.
I am trying to write a query to find the score rank of a user's games. I need it to take in a user id and then return that user's relative ranking to other user's scores. There is a user and a game table. The game table has a userId field with a one-to-many relationship.
示例表:
用户:id freebee1 102 13
users: id freebee 1 10 2 13
游戏:用户 ID 分数1 151 202 101 15
games: userId score 1 15 1 20 2 10 1 15
将 $id 1 传递给这个函数应该返回值 1,因为用户 1 当前得分最高.同样,用户 2 将返回 2.
passing $id 1 into this function should return the value 1, as user 1 currently has the highest score. Likewise, user 2 would return 2.
目前这是我所拥有的:
SELECT outerU.id, ( SELECT COUNT( * ) FROM users userI, games gameI WHERE userI.id = gameI.userId AND userO.id = gameO.userId AND ( userI.freebee + SUM(gameI.score) ) >= ( userO.freebee + SUM(gameO.score) ) ) AS rank FROM users userO, games gameO WHERE id = $id这给了我一个无效使用组功能"的错误.有什么想法吗?
Which is giving me an "invalid use of group function" error. Any ideas?
推荐答案 SELECT u.id,total_score, ( SELECT COUNT(*) FROM (SELECT u1.id, (IFNULL(u1.freebee,0)+ IFNULL(SUM(score),0)) as total_score FROM users u1 LEFT JOIN games g ON (g.userId = u1.id) GROUP BY u1.id )x1 WHERE x1.total_score > x.total_score )+1 as rank, ( SELECT COUNT(DISTINCT total_score) FROM (SELECT u1.id, (IFNULL(u1.freebee,0)+ IFNULL(SUM(score),0)) as total_score FROM users u1 LEFT JOIN games g ON (g.userId_Id = u1.id) GROUP BY u1.id )x1 WHERE x1.total_score > x.total_score )+1 as dns_rank FROM users u LEFT JOIN ( SELECT u1.id, (IFNULL(u1.freebee,0)+ IFNULL(SUM(score),0)) as total_score FROM users u1 LEFT JOIN games g ON (g.userId = u1.id) GROUP BY u1.id )x ON (x.id = u.id)rank -(正常等级 - 例如 - 1,2,2,4,5),dns_rank - 密集等级(1,2,2,3,4).列 total_score - 仅用于调试...
rank - (normal rank - e.g. - 1,2,2,4,5), dns_rank - dense rank (1,2,2,3,4). Column total_score - just for debugging...
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