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问题描述
我一直收到以下错误
错误:错误:语法错误,无法识别的表达式:table $ MainContent $ gridPlans $ ctl02 $ chkSelected 源文件: code.jquery/jquery-latest.min.js 行:2
Error: Error: Syntax error, unrecognized expression: table $MainContent$gridPlans$ctl02$chkSelected Source File: code.jquery/jquery-latest.min.js Line: 2
我已经处理了脚本的哪个部分导致了这个问题,但不确定如何修复它:
I have worked what part of the script is causing this issue but unsure how to fix it:
// Check Box selector $("input:checkbox:not(:checked)").each(function () { var column = "table ." + $(this).attr("name"); // this line is not working $(column).hide(); }); $("input:checkbox").click(function () { var column = "table ." + $(this).attr("name"); $(column).toggle(); }); // Manage column checkboxes that should be unchecked function manChecks() { var __CS = document.getElementById('__CS'); var cols = __CS.value; // this line also causing issues colManage(1, cols.indexOf('|1') != -1); colManage(2, cols.indexOf('|2') != -1); colManage(3, cols.indexOf('|3') != -1); colManage(5, cols.indexOf('|5') != -1); colManage(6, cols.indexOf('|6') != -1); colManage(7, cols.indexOf('|7') != -1); colManage(8, cols.indexOf('|8') != -1); colManage(9, cols.indexOf('|9') != -1); } function colManage(id, show) { document.getElementById(id).checked = show; var column = "table ." + id; if (show) { $(column).show(); $('label[for=' + id + ']').addClass('checked') } else { $(column).hide(); $('label[for=' + id + ']').removeClass('checked') } }推荐答案
您的班级选择器中包含 $ 字符 - 这些需要被转义。
Your class selector has $ characters in it - these need to be escaped.
需要转义jQuery选择器字符串中的特殊字符
jQuery选择器值转义
samuelsjoberg/archive/2009/09/escape-jquery-selectors
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错误:错误:语法错误,无法识别的表达式:
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