在SQL查询中自动递增varchar

本文介绍了在SQL查询中自动递增varchar的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我正在尝试从表中自动增加varchar列.它以"PU"为前缀.我用它来抓取最后一个数字并将其递增一个.

I am trying to auto increment a varchar column from a table. It is prefix with "PU". I use this to grab the last number and increment it by one.

我在下面尝试了此查询:

I tried this query below:

SELECT CONCAT( LEFT( BARCODE, 2 ) , MAX( RIGHT( BARCODE, LENGTH(BARCODE)-2 ) * 1 ) +1 ) as newbarcode FROM KGU WHERE HW_TYPE='STANDARD PURGE UNIT';

最后一个条形码是PU0000012.它返回一个PU13.它将删除0.

The last barcode is PU0000012. It returns a PU13. It removes the 0.

所以我尝试将其替换为:

So I tried replacing it with:

LEFT( BARCODE, 7 )

它返回了正确的PU0000013.但是，假设我将PU1234567作为最后一个条目.它返回:PU000001234568.

It returned PU0000013 which is correct. But suppose I put a PU1234567 as last entry. It returns: PU000001234568.

有什么建议吗?我正在使用php btw.如果可以选择使用php，我可以接受.但是我更愿意在可能的情况下在sql查询中解决该问题.

Any suggestions? I am using php btw. If an option is to use php I am open to it. But I prefer it to be solve in sql query if possible.

推荐答案

尝试一下:

<?php // fetch the very last entry $Barcode = 'PU000001234567'; preg_match("/(\D+)(\d+)/", $Barcode, $Matches); // Matches the PU and number $ProductCode = $Matches[1]; $NewID = intval($Matches[2]); $NewID++; $BarcodeLength = 12; $CurrentLength = strlen($NewID); $MissingZeros = $BarcodeLength - $CurrentLength; for ($i=0; $i<$MissingZeros; $i++) $NewID = "0" . $NewID; $Result = $ProductCode . $NewID; echo $Result; // insert into database with $Result

返回:PU000001234568

Returns: PU000001234568