从字符串创建对象

本文介绍了从字符串创建对象的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

大家好， 关于这个主题有一些问题和答案，但是，没有一个能解决我的问题。我是一个关于c＃的新手。 我是一个班级并且有一个字符串值。如果字符串值与类名相同，则从该类创建新对象。 字符串值是基本 和班级名称是基本 我知道解决方案是Assembly.CreateInstance，但它总是为空，无法成功创建任何实例。 名称：TTT Publickeytoken = null CodeBase：TTT.exe文件的路径 我尝试过：

命名空间TTT { public class Basic { public string Id {get;组; public int SourceSystem {get;组; } } 公共类Message_Tag_Info { public string Id {get;组; } 公共字符串ClassCode {get;组; } 公共字符串ClassName {get;组; } } class程序 { static void Main（string [] args） { Message_Tag_Info message = new Message_Tag_Info（） ; string tmp =Basic; message.ClassName = tmp; 类型t = Type.GetType（TTT。+ message.ClassName）; Assembly assem = Assembly.GetAssembly（t）; Console.WriteLine（Name：{0}，assem.FullName）; Console.WriteLine（CodeBase：{0}，assem.CodeBase）; var obj = Assembly.GetExecutingAssembly（）。CreateInstance（message.ClassName）; Console.ReadLine（）; } } }

解决方案

你试过吗？ Activator.CreateInstance，下面是几个例子，我希望这有帮助 c＃ - 创建一个类名的对象实例，其名称在字符串变量中 - Stack Overflow c＃ - 从字符串创建类的实例 - Stack Overflow

你只是在基本上做CreateInstance而且这还不足以反映出你的意思是什么类，它需要全名TTT.Basic 下面我使用t.FullName代替

var obj = Assembly.GetExecutingAssembly（ ）.CreateInstance（t.FullName）;

Hi all, There are some questions and answers about this topic but, none of them solve my issue. I am a quite new about c#. I've a class and had a string value. If the string value same with class name, create new object from that class. string value is "Basic" and class name is "Basic" I know the solution is Assembly.CreateInstance but it always gets null , could not success to create any instance. Name:TTT Publickeytoken=null CodeBase: path to TTT.exe file What I have tried:

namespace TTT { public class Basic { public string Id { get; set; } public int SourceSystem { get; set; } } public class Message_Tag_Info { public string Id { get; set; } public string ClassCode { get; set; } public string ClassName { get; set; } } class Program { static void Main(string[] args) { Message_Tag_Info message = new Message_Tag_Info(); string tmp = "Basic"; message.ClassName = tmp; Type t = Type.GetType("TTT."+message.ClassName); Assembly assem = Assembly.GetAssembly(t); Console.WriteLine("Name: {0}", assem.FullName); Console.WriteLine("CodeBase: {0}", assem.CodeBase); var obj = Assembly.GetExecutingAssembly().CreateInstance(message.ClassName); Console.ReadLine(); } } }

解决方案

Have you tried Activator.CreateInstance, below are few examples, I hope this helps c# - Create object instance of a class having its name in string variable - Stack Overflow c# - Create an instance of a class from a string - Stack Overflow

You're doing CreateInstance on just "Basic" and that's not enough for reflection to work out what class you mean, it needs the full name of TTT.Basic Below I use t.FullName instead

var obj = Assembly.GetExecutingAssembly().CreateInstance(t.FullName);