和结果是1,2,3,4,5,6
And the result is 1,2,3,4,5,6
推荐答案您想要使用所有,而不是任何。从精细的手工:
You want to use ALL, not ANY. From the fine manual:
9.21.3。 ANY / SOME(阵列)
expression operator ANY (array expression)[...]左侧前pression进行评估,并使用相比,数组的每个元素给定的的运营商的,它必须产生一个布尔结果。结果任何如果获得任何真正的结果就是真。
[...] The left-hand expression is evaluated and compared to each element of the array using the given operator, which must yield a Boolean result. The result of ANY is "true" if any true result is obtained.
因此,如果我们要说的是:
So if we say this:
1 != any(array[1,2])然后我们会得到正确的,因为(1!= 1)或(1!= 2)是真实的。 任何本质上是一个或运营商。例如:
then we'll get true since (1 != 1) or (1 != 2) is true. ANY is essentially an OR operator. For example:
=> select id from (values (1),(2),(3)) as t(id) where id != any(array[1,2]); id ---- 1 2 3 (3 rows)如果我们看一下ALL,我们看到:
If we look at ALL, we see:
9.21.4。 ALL(阵列)
expression operator ALL (array expression)[...]左侧前pression进行评估,并使用相比,数组的每个元素给定的的运营商的,它必须产生一个布尔结果。 所有结果是真,如果所有的比较产生真正的...
[...] The left-hand expression is evaluated and compared to each element of the array using the given operator, which must yield a Boolean result. The result of ALL is "true" if all comparisons yield true...
因此,如果我们要说的是:
so if we say this:
1 != all(array[1,2])然后我们会得到错误的,因为(1!= 1)和(1!= 2)是假的,我们将看到所有本质上是一个和运营商。例如:
then we'll get false since (1 != 1) and (1 != 2) is false and we see that ALL is essentially an AND operator. For example:
=> select id from (values (1),(2),(3)) as t(id) where id != all(array[1,2]); id ---- 3 (1 row)如果要排除数组中的所有值,可以使用所有:
If you want to exclude all values in an array, use ALL:
select "Ticket_id" from "Tickets" where "Status" = 1 and "Ticket_id" != all(array[1,2,3]) limit 6更多推荐
PostgreSQL的查询与“任意”不工作
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