本文介绍了避免使用math.random()再次出现相同的值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
animations = ['fadeIn','fadeInDown','slideInUp','flipInY','bounceInLeft'];
首先对数组进行随机排序,然后从索引0到5逐一遍历,然后根据需要进行多次循环.
选择一个随机元素并将其切成薄片,直到阵列为空,然后从备份中刷新阵列. (请注意,不要使用参考进行备份,否则备份阵列会随着拼接而被删除.因此请使用.slice())
想象一下,每当用户单击某个内容时,我都会产生随机效果,因此,为了获得最佳体验,我希望用户也具有相同的效果.但是使用
Imagine I generate random effect whenever user click something, so to achieve best experience, I would want the user to have same effect. But with
animations[ Math.floor(Math.random() * animations.length) -1];那会发生的.
如何避免相同的值再次出现?
How to avoid same value to appear again?
推荐答案我可以提出两种建议.
Array.prototype.shuffle = function(){ var a = this.slice(), // don't morph the original i = a.length, j; while (i > 1) { j = ~~(Math.random()*i--); a[i] = [a[j],a[j]=a[i]][0]; } return a; }; var album = ["photo1","photo2","photo3","photo4","photo5"]; photos = album.shuffle(); photos.forEach(p => console.log(p)); console.log("another way") // the splice way photos = album.slice(); while (photos.length) console.log(photos.splice(Math.floor(Math.random() * photos.length),1)[0]); !photos.length && (photos = album.slice()); // restore photos album and continue while (photos.length) console.log(photos.splice(Math.floor(Math.random() * photos.length),1)[0]); !photos.length && (photos = album.slice()); // restore photos album and continue
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避免使用math.random()再次出现相同的值
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