c是经过解析的python代码树:
c is a parsed tree of a python code:
c = ast.parse(''' for x in y: print(x)''')
d是tree-c的转储文件
d is the dump file of tree-c
d=ast.dump(c)d的内容为以下字符串:
the content of d is the following string:
Module( body=[For(target=Name(id='x', ctx=Store()), iter=Name(id='y', ctx=Load()), body=[Expr(value=Call(func=Name(id='print', ctx=Load()), args=[Name(id='x', ctx=Load())], keywords=[]))], orelse=[])])我环顾四周,看看是否可以找到方法使用d的内容,返回到树c。
I've looked around the net to see if I could find a method to use the content of d, to revert back to the tree c.
有什么建议吗?
谢谢
推荐答案您可以使用 eval 来获取 ast 字符串中的对象:
You can use eval to get the ast object from the string:
ast_obj = eval(d)然后,存在第三种可以转换回源代码的第三方库(使用AST,是否有一个可用的库来获取源代码?, Python ast(抽象语法树):获取子节点的源字符串)
Then, there exist various third party libraries that can convert back to source (Given an AST, is there a working library for getting the source?, Python ast (Abstract Syntax Trees): get back source string of subnode)
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有什么办法可以从树的转储文件中还原AST树?
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