问题 我正在按需要获得o / p但是您可以看到我的电话号码在文件中列为列表。但是如何从混合数据中仅提取电话号码以及如何从混合数据中显示最常用的数字。 Lorem ipsum dolor sit amet,consectetur adipiscing elit,sed do eiusmod tempor incididunt ut labore et dolore magna aliqua。 Ut enim ad minim veniam,quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat。 Duis aute irure dolor in repreptderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur。 Excepteur sint occaecat cupidatat non proident,sunt in culpa qui officia deserunt mollit anim id est laborum。 1.Phone number 1:(999)999-3333 2.电话号码2:(888)999 -2212 3.电话号码3:(111)222 - 2223 4.电话号码4 :(999 )999-3333 5.电话号码5:(888)222-2222 Duis aute irure dolor in repreptderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur。 Excepteur sint occaecat cupidatat non proident,sunt in culpa qui officia deserunt mollit anim id est laborum。 6.电话号码:(999 )999-3333
< pre lang =text>我尝试了什么: 来自收藏品进口柜台 text ='''\ (999)999-3333 (888)999-2212 (111)222-2223 (999) )999-3333 (888)222-2222 (999)999-3333 ''' counter =柜台() for text in .phlit('\ n'): counter [phone] + = 1 print counter.most_common(1)
解决方案我可能正在使用正则表达式 7.2。 re - 正则表达式操作 - Python 2.7.12文档 [ ^ ]
QuestionI am getting o/p as desired but as you can see my phone numbers are listed as list in the file. but how do I extract only phone numbers from the mixed data and how do I display most frequent numbers from that mixed data. Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat. Duis aute irure dolor in reprehenderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur. Excepteur sint occaecat cupidatat non proident, sunt in culpa qui officia deserunt mollit anim id est laborum. 1.Phone number 1: (999) 999-3333 2.phone number 2: (888) 999 -2212 3.Phone number 3: (111) 222 - 2223 4.Phone number 4: (999)999-3333 5.Phone number 5: (888)222-2222 Duis aute irure dolor in reprehenderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur. Excepteur sint occaecat cupidatat non proident, sunt in culpa qui officia deserunt mollit anim id est laborum. 6.Phone number: (999)999-3333
<pre lang="text">What I have tried: from collections import Counter text = '''\ (999) 999-3333 (888) 999-2212 (111) 222-2223 (999) 999-3333 (888) 222-2222 (999) 999-3333 ''' counter = Counter() for phone in text.split('\n'): counter[phone] += 1 print counter.most_common(1)
解决方案 I'd likely be using a Regular Expression 7.2. re — Regular expression operations — Python 2.7.12 documentation[^]更多推荐
例如:me.txt(包含数据和电话号码),其信息低于信息
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