本文介绍了如果满足条件,则将列的总和分配给另一列中的一个日期的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
DB-Fiddle:
CREATE TABLE sales ( id int auto_increment primary key, customerID VARCHAR(255), sales_date DATE, sales_volume INT, annual_unqiue_count INT ); INSERT INTO sales (customerID, sales_date, sales_volume, annual_unqiue_count) VALUES ("Customer_01", "2020-03-01", "600", "1"), ("Customer_01", "2020-03-25", "315", "0"), ("Customer_02", "2020-03-18", "208", "1"), ("Customer_02", "2020-07-25", "140", "0"), ("Customer_03", "2020-10-18", "400", "1"), ("Customer_03", "2020-12-06", "500", "0"), ("Customer_03", "2020-12-18", "438", "0"), ("Customer_03", "2020-12-25", "917", "0");预期结果:
customerID sales_date SUM(annual_unqiue_count) SUM(sales_volume) Customer_01 2020-03-01 1 915 (=600+315) Customer_01 2020-03-25 0 0 Customer_02 2020-03-18 1 348 (=208+140) Customer_02 2020-07-25 0 0 Customer_03 2020-10-18 1 2255 (=400+500+438+917) Customer_03 2020-12-06 0 0 Customer_03 2020-12-18 0 0 Customer_03 2020-12-25 0 0在结果中,我想将每个 customer 的 SUM(sales_volume) 分配 到 sales_dateannual_unqiue_count <>0.
到目前为止,我尝试使用此查询,但无法使其工作:
So far I tried to go with this query but could not make it work:
SELECT customerID, sales_date, SUM(annual_unqiue_count), SUM(sales_volume) FROM sales GROUP BY 1,2 HAVING SUM(annual_unqiue_count) <> 0;我需要改变什么才能得到预期的结果?
What do I need to change to get the expected result?
推荐答案你想要窗口函数:
select s.*, (case when annual_unqiue_count <> 0 then sum(sales_volume) over (partition by customerId) else 0 end) as sales_volume from sales s;更多推荐
如果满足条件,则将列的总和分配给另一列中的一个日期
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