从数据库+ AJAX + PHP加载数据

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我有一个关于从数据库加载多个领域，并利用它们在JavaScript的问题。

I have a question about loading multiple fields from the database and use them in javascript.

这是我的表死亡与字段：

This is my table "deaths" with fields:

- district - year_1999 - year_2000 - year_2001 - year_2002 - year_2003 - year_2004 - year_2005 - year_2006 - year_2007 - year_2008 - year_2009

现在我要加载的字段一年_....时区='districtname

Now I want to load the fields year_.... when district = 'districtname'

这是我有什么：（PHP）

This is what I have: (PHP)

$host = "localhost"; $user = "root"; $pass = "root"; $databaseName = "testdatabase"; $tableName = "deaths"; //-------------------------------------------------------------------------- // 1) Connect to mysql database //-------------------------------------------------------------------------- $con = mysql_connect($host,$user,$pass); $dbs = mysql_select_db($databaseName, $con); //-------------------------------------------------------------------------- // 2) Query database for data //-------------------------------------------------------------------------- $result = mysql_query("SELECT year_1999,year_2000,year_2001,year_2002,year_2003,year_2004,year_2005,year_2006,year_2007,year_2008,year_2009 FROM $tableName WHERE district = 'Binnenstad'"); //query $data = array(); while ( $row = mysql_fetch_row($result) ) { $data[] = $row; } echo json_encode( $data );

JavaScript的：

Javascript:

$(function () { //----------------------------------------------------------------------- // 2) Send a http request with AJAX api.jquery/jQuery.ajax/ //----------------------------------------------------------------------- $.ajax({ url: './api4.php', //the script to call to get data data: "", //you can insert url argumnets here to pass to api.php //for example "id=5&parent=6" dataType: 'json', //data format success: function(rows) //on recieve of reply { //-------------------------------------------------------------------- // 3) Update html content //-------------------------------------------------------------------- for (var i in rows) { var row = rows[i]; var data = row[0]; $('#districts ul').append("<li>" + data + "</li>") .append(); } } }); });

但是，这只能显示第一列数据（year_1999）。

But this only shows the first column data (year_1999).

我该如何解决这个问题？

How can I fix this?

推荐答案

而不是的（VAR我行）... 尝试：

更新。寻找你的PHP接近试试像此画每年：

UPDATE. Looking your php closer try something like this to draw each year:

$.each(rows, function(i, data) { $.each(data, function(j, year) { $('#districts ul').append("<li>" + year + "</li>") }); });