为什么我的代码没有打印到stdout？

本文介绍了为什么我的代码没有打印到stdout？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我正在尝试计算学生分数的平均值：

I'm trying to calculate the average of a student's marks:

import java.util.Scanner; public class Average { public static void main(String[] args) { int mark; int countTotal = 0; // to count the number of entered marks int avg = 0; // to calculate the total average Scanner Scan = new Scanner(System.in); System.out.print("Enter your marks: "); String Name = Scan.next(); while (Scan.hasNextInt()) { mark = Scan.nextInt(); countTotal++; avg = avg + ((mark - avg) / countTotal); } System.out.print( Name + " " + avg ); } }

推荐答案

这里是一个使用两个 Scanner 的解决方案（如我的上一个答案）。

Here's a solution that uses two Scanner (as suggested in my previous answer).

• 扫描仪stdin =新扫描仪（System.in）; 扫描用户输入
• 扫描仪得分=新扫描仪（ stdin.nextLine（））; 扫描包含分数的行

• Scanner stdin = new Scanner(System.in); scans user's input
• Scanner scores = new Scanner(stdin.nextLine()); scans the line containing the scores

另请注意，它使用了很多用于计算平均值的更简单，更易读的公式。

Note also that it uses a much simpler and more readable formula for computing the average.

Scanner stdin = new Scanner(System.in); System.out.print("Enter your average: "); String name = stdin.next(); int count = 0; int sum = 0; Scanner scores = new Scanner(stdin.nextLine()); while (scores.hasNextInt()) { sum += scores.nextInt(); count++; } double avg = 1D * sum / count; System.out.print(name + " " + avg);

样本输出：

Enter your average: Joe 1 2 3 Joe 2.0