在 MySQL 中对具有权重的匹配标签上的项目进行排序

本文介绍了在 MySQL 中对具有权重的匹配标签上的项目进行排序的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我很难在这里找到正确的查询/查询.当您想使用标签查找相关项时，在 MySQL 中，您可以使用常用标签计数"来查找最相似的项.

I'm having a hard time to get to the right query/queries here. When you want to find related items using tags, in MySQL, you can use a 'common tag count' to find items that are most similar.

假设我的架构如下所示:

Say my schema looks like this:

• 标签(tag_id，标题)
• 文章(article_id, some_text)
• articles_tags(tag_id, article_id)

然后，您可以获取项目并在常见标签上对它们进行排序，例如文章 2"，如下所示:

Then you can get items and sort them on common tags with 'article 2' for example, like this:

SELECT at1.article_id, Count(at1.tag_id) AS common_tag_count FROM articles_tags AS at1 INNER JOIN articles_tags AS at2 ON at1.tag_id = at2.tag_id WHERE at2.article_id = 2 GROUP BY at1.article_id HAVING at1.article_id != 2 ORDER BY common_tag_count DESC;

但在我的情况下，有一个挑战.我想根据多篇文章而不是一篇文章(类似于阅读历史")找到类似的文章.如果 2 篇文章都有标签 X，我希望标签 X 变得更重要.

But in my situation, there's a challenge. I want to find similar articles based on multiple articles instead of one (something like a "read history"). And if 2 articles both have tag X, I want tag X to become more important.

所以基本上，我正在寻找一种方法来进行 common_tag_count 匹配，但具有标签的权重.任何人都知道如何做到这一点?

So basicly, I'm looking for a way to do a common_tag_count match but with a weight for tags. Anyone has any idea how to accomplish this?

推荐答案

要获取多篇文章使用的标签，包括使用频率，可以使用这个查询:

To get the tags used by the multiple articles, including how often they are used, you can use this query:

SELECT tag_id, COUNT(article_id) as tag_weight FROM articles_tags WHERE article_id IN ( /* Read articles */ 1, 2 ) GROUP BY tag_id;

要根据该选择获取类似文章，您必须在已有的类似联接中使用上述查询:

To get the similar articles based on that selection you have to use above query in a similar join as you already have:

SELECT articles.article_id, articles.title, SUM(tag_weights.tag_weight) FROM articles JOIN articles_tags ON articles_tags.article_id = articles.article_id JOIN ( SELECT tag_id, COUNT(article_id) as tag_weight FROM articles_tags WHERE article_id IN ( /* Read articles */ 1, 2 ) GROUP BY tag_id ) AS tag_weights ON articles_tags.tag_id = tag_weights.tag_id WHERE articles.article_id NOT IN ( /* Read articles */ 1, 2 ) GROUP BY articles.article_id ORDER BY SUM(tag_weights.tag_weight) DESC;

我们在可以访问标签权重的子查询上添加了一个额外的 JOIN.使用 ORDER BY，您将首先获得最佳"结果.

We're adding an extra JOIN here on the subquery which has access to the tag-weights. Using the ORDER BY you get the 'best' results first.

演示:www.sqlfiddle/#!2/b35432/2/1(阅读文章 1 和 2，给标签 1 的权重为 2，给标签 2 的权重为 1).

Demo: www.sqlfiddle/#!2/b35432/2/1 (articles 1 and 2 are read, giving tag 1 a weight of 2, tag 2 a weight of 1).