取消设置多个数组元素的更好方法

本文介绍了取消设置多个数组元素的更好方法的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

这里的问题是我有一个包含17个元素的数组.我想获取需要的元素一段时间，然后将其从数组中永久删除.

The deal here is that I have an array with 17 elements. I want to get the elements I need for a certain time and remove them permanently from the array.

代码如下:

$name = $post['name']; $email = $post['email']; $address = $post['address']; $telephone = $post['telephone']; $country = $post['country']; unset($post['name']); unset($post['email']); unset($post['address']); unset($post['telephone']); unset($post['country']);

是的，代码很丑陋，无需扑朔迷离.如何使它看起来更好?

Yes the code is ugly, no need to bash. How do I make this look better?

推荐答案

它看起来像函数 extract() 将是您尝试做的更好的工具(假设它从数组中提取所有键/值，并将它们分配给与本地作用域中的键具有相同名称的变量).提取内容后，假设未包含任何其他内容，您可以取消设置整个$post.

但是，要真正回答您的问题，您可以创建要删除并遍历的键的数组，显式取消设置它们...

However, to actually answer your question, you could create an array of the keys you want to remove and loop through, explicitly unsetting them...

$removeKeys = array('name', 'email'); foreach($removeKeys as $key) { unset($arr[$key]); }

...或者您可以将变量指向删除了键的新数组...

...or you could point the variable to a new array that has the keys removed...

$arr = array_diff_key($arr, array_flip($removeKeys));

...或将所有数组成员传递给unset() ...

...or pass all of the array members to unset()...

unset($arr['name'], $arr['email']);