如何批量创建嵌套变量?

本文介绍了如何批量创建嵌套变量?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我正在尝试创建的批处理游戏中获取嵌套变量. 我希望它可以选择一个随机变量并将其更改为X，但是如果已经选择它，则应返回并选择另一个数字.

I am trying to get nested variables in my batch game i am creating. I want it so that it will choose a random variable and change it to X, but if it is already chosen, it should go back and choose a different number.

set 1=a set 2=b set 3=c set 4=d set 5=e

这些是变量，这是代码

setlocal enabledelayedexpansion :eliminator set /a eliminate=(%random * 5) / 32767 + 1 if %%eliminate%%==X goto eliminator echo The letter !!eliminate!! was chosen timeout 5 set %%eliminate%%=X goto eliminator

现在，事情是，当我尝试回显它时，它会写出变量的名称而不是值.同样，已经选择的变量将再次被选择.有什么办法可以解决这个问题吗?谢谢.

Now, the thing is, when I try to echo it, it writes the name of the variable instead of the value. Also, variables that have already been chosen are being chosen again. Any way I could fix this? Thanks.

推荐答案

尝试一下:

@echo off&setlocal set "var1=a" set "var2=b" set "var3=c" set "var4=d" set "var5=e" :loop set /a rd=%random%%%5+1 if defined var%rd% call echo %%var%rd%%% set "var%rd%=" set "var" >nul 2>&1 && goto:loop

..输出(可能有所不同):

..output (may vary):

d a c b e