以编程方式为Spring创建JNDI DataSource

本文介绍了以编程方式为Spring创建JNDI DataSource的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我有一个现有的基于Spring网络的应用程序，其中包含使用JNDI定义的数据源，我正在尝试创建一个独立的应用程序来使用这些bean。如何在独立应用程序中以编程方式创建JNDI条目和数据库属性？

I have an existing Spring web-based application that has datasources defined using JNDI, and I'm trying to create a standalone app to use the beans. How can I create the JNDI entry and database properties programmatically in the standalone application?

<bean id="myDataSource" class="org.springframework.jndi.JndiObjectFactoryBean"> <property name="jndiName" value="java:comp/env/jdbc/MyDS" /> </bean> public static void main(String[] args) { // this throws an error since the JNDI lookup fails - can I programmatically define the database properties here? ClassPathXmlApplicationContext ctx = new ClassPathXmlApplicationContext("applicationContext.xml"); UserService userService = ctx.getBean(UserService.class); User user = userService.findUserById("jdoe"); System.out.println("display name: " + user.getDisplayName()); }

编辑：

我尝试了类似的东西，但现在收到错误javax.naming.NoInitialContextException：需要在环境或系统属性中指定类名

I tried something like this, but am now getting the error "javax.naming.NoInitialContextException: Need to specify class name in environment or system property"

public static void main(String[] args) { setupJNDI(); ClassPathXmlApplicationContext ctx = new ClassPathXmlApplicationContext("applicationContext.xml"); UserService userService = ctx.getBean(UserService.class); User user = userService.findUserById("jdoe"); System.out.println("display name: " + user.getDisplayName()); } private static void setupJNDI() { InitialContext ic; try { ic = new InitialContext(); ic.createSubcontext("java:"); ic.createSubcontext("java:/comp"); ic.createSubcontext("java:/comp/env"); ic.createSubcontext("java:/comp/env/jdbc"); SQLServerConnectionPoolDataSource myDS = new SQLServerConnectionPoolDataSource(); opaDS.setServerName("myserver"); opaDS.setPortNumber(1433); opaDS.setUser("user"); opaDS.setPassword("password"); ic.bind("java:/comp/env/jdbc/MyDS", myDS); } catch (NamingException e) { e.printStackTrace(); } }

推荐答案

org.springframework.test 依赖项通过 SimpleNamingContextBuilder ：

The org.springframework.test dependency has support for that via the SimpleNamingContextBuilder:

// First create the mock JNDI tree and bind the DS SimpleNamingContextBuilder builder = new SimpleNamingContextBuilder(); DataSource ds = new ComboPooledDataSource(); ds.setDriverClass( ... ); // etc. for uid, password, url builder.bind( "java:comp/env/jdbc/MyDS" , ds ); builder.activate(); // Then create the Spring context, which should now be able // to resolve the JNDI datasource ApplicationContext context = new ClassPathXmlApplicationContext( "..." );

这应该有效。

干杯，