我有两个 mysql 表 - 一个销售表:
I have two mysql tables - a sales table:
+----------------+------------------------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +----------------+------------------------------+------+-----+---------+-------+ | StoreId | bigint(20) unsigned | NO | PRI | NULL | | | ItemId | bigint(20) unsigned | NO | | NULL | | | SaleWeek | int(10) unsigned | NO | PRI | NULL | | +----------------+------------------------------+------+-----+---------+-------+和一个项目表:
+--------------------+------------------------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +--------------------+------------------------------+------+-----+---------+-------+ | ItemId | bigint(20) unsigned | NO | PRI | NULL | | | ItemName | varchar(100) | NO | | NULL | | +--------------------+------------------------------+------+-----+---------+-------+销售表包含每个 ItemID 的多个记录 - 每个 SaleWeek 一个.我想通过加入两个表格来选择所有出售的商品,如下所示:
The sales table contains multiple records for each ItemID - one for each SaleWeek. I want to select all items sold by joining the two tables like so:
SELECT items.ItemName, items.ItemId FROM items JOIN sales ON items.ItemId = sales.ItemId WHERE sales.StoreID = ? ORDER BY sales.SaleWeek DESC;但是,这会根据每个 SaleWeek 的多个条目返回多个 ItemId 值.我可以做一个不同的选择来只返回一个 ItemID - 我不想查询最新的 SaleWeek,因为有些项目可能没有最新的条目SaleWeek 所以我需要获得最后一次销售.我是否需要指定 DISTINCT 或使用 LEFT OUTER JOIN 或其他什么?
However, this is returning multiple ItemId values based on the multiple entries for each SaleWeek. Can I do a distinct select to only return one ItemID - I don't want to have to query for the latest SaleWeek because some items may not have an entry for the latest SaleWeek so I need to get the last sale. Do I need to specify DISTINCT or use a LEFT OUTER JOIN or something?
推荐答案DISTINCT 应该可以满足您的需求:
A DISTINCT should do what you're looking for:
SELECT DISTINCT items.ItemName, items.ItemId FROM items JOIN sales ON items.ItemId = sales.ItemId WHERE sales.StoreID = ? ORDER BY sales.SaleWeek DESC;那只会返回不同的 items.ItemName, items.ItemId 元组.
That would return only distinct items.ItemName, items.ItemId tuples.
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在连接上选择不同的记录
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