ORACLE(11.2.0.1.0)

本文介绍了ORACLE(11.2.0.1.0)-具有日期表达式的递归CTE的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

以下问题的正确答案:

• 如果我没有记错的话，那是在11.2.0.3或更高版本中修复的错误. (仍然不再支持11.2.0.1.11.2.0.4是唯一仍受支持的11.2版本)– @a_horse_with_no_name
• 错误号为11840579，已在11.2.0.3和12.1.0.1中修复. – @a_horse_with_no_name

• That is a bug that was fixed in 11.2.0.3 or later if I recall correctly. (11.2.0.1 is no longer supported anyway. 11.2.0.4 is the only 11.2 release that is still supported) – @a_horse_with_no_name
• The bug number is 11840579 and it was fixed in 11.2.0.3 and 12.1.0.1 – @a_horse_with_no_name

问题

我有一张桌子

CREATE TABLE test( from_date date, to_date date ); INSERT INTO test(from_date,to_date) --VALUES('20171101','20171115'); VALUES(TO_DATE('20171101','YYYYMMDD'),TO_DATE('20171115','YYYYMMDD'));

Oracle中的以下查询仅返回一行(预期为15行)

The following query in Oracle return only one row (expected 15 rows)

WITH dateCTE(from_date,to_date,d,i) AS( SELECT from_date,to_date,from_date AS d,1 AS i FROM test UNION ALL SELECT from_date,to_date,d+INTERVAL '1' DAY,i+1 FROM dateCTE WHERE d<to_date ) SELECT d,i FROM dateCTE

SQL提琴- sqlfiddle/#!4/36907/8

为了进行测试，我将条件更改为i<10

For test I changed the condition to i<10

WITH dateCTE(from_date,to_date,d,i) AS( SELECT from_date,to_date,from_date AS d,1 AS i FROM test UNION ALL SELECT from_date,to_date,d+INTERVAL '1' DAY,i+1 FROM dateCTE --WHERE d<to_date WHERE i<10 -- exit condition ) SELECT d,i FROM dateCTE

并获得下一个结果

| D | I | |------------|----| | 2017-11-01 | 1 | | 2017-10-31 | 2 | | 2017-10-30 | 3 | | 2017-10-29 | 4 | | 2017-10-28 | 5 | | 2017-10-27 | 6 | | 2017-10-26 | 7 | | 2017-10-25 | 8 | | 2017-10-24 | 9 | | 2017-10-23 | 10 |

为什么此递归查询在Oracle中返回不良结果?

Why do this recursive query returned bad result in Oracle?

SQL小提琴- sqlfiddle/#!4/36907/5

我在SQLServer中运行了类似的查询，并且得到了正确的结果

I ran a similar query in SQLServer and I get the right result

WITH dateCTE(from_date,to_date,d,i) AS( SELECT from_date,to_date,from_date AS d,1 AS i FROM test UNION ALL SELECT from_date,to_date,DATEADD(DAY,1,d),i+1 FROM dateCTE WHERE d<to_date ) SELECT d,i FROM dateCTE

正确的结果

d i 2017-11-01 1 2017-11-02 2 2017-11-03 3 2017-11-04 4 2017-11-05 5 2017-11-06 6 2017-11-07 7 2017-11-08 8 2017-11-09 9 2017-11-10 10 2017-11-11 11 2017-11-12 12 2017-11-13 13 2017-11-14 14 2017-11-15 15

为什么它在Oracle中不起作用?您可以建议哪些替代方案?谢谢！

Why it doesn't work in Oracle? What alternative variants can you suggest? Thank you!

真实系统中的屏幕截图:

推荐答案

如果您要按顺序从起始日期到当前日期，请使用以下选择:

If you want to have a sequential from-date to to-date, Use such this select:

SELECT DATE '2017-11-01' + LEVEL - 1 AS D, LEVEL AS I FROM DUAL CONNECT BY LEVEL <= DATE '2017-11-15' - DATE '2017-11-01' + 1;