我想能够在我的程序中实现一个条件,它只运行N个小时,也许用户可以指定N,但是我们不能前进。
$ b $我想我可以使用 datetime.now()并将以下值存储在变量中, time >>>时间>>>> time = datetime.datetime(2013,12,9,21,50,32,405329)任何关于我如何可以访问( - )之间的第四个字段的想法,看到它是一个字符串?
我的条件将像,而time!= timeEnd 其中timeEnd将是以下值: p>
>>> timeEnd = datetime.datetime(2013,12,9,21 + N,50,32,405329)
谢谢
解决方案您可以将 timedelta 添加到 datetime 获得一个新的 datetime 。
>> ;> import datetime >>>> now = datetime.datetime.now()>>> end_time = now + datetime.timedelta(hours = 6)>>>现在打印 2013-12-09 17:03:06.979628 >>> print end_time 2013-12-09 23:03:06.979628 >>>然后...
while datetime.datetime.now()< end_time: pass#do work
I want to be able to implement a condition in my program where it would only run for N number of hours, maybe the user could specify N, but let's not jump ahead.
I figured I could use datetime.now() and store the value below in a variable, time
>>> time >>> time = datetime.datetime(2013, 12, 9, 21, 50, 32, 405329)Any ideas on how I can access the fourth field between the (--), seeing as it's a string?
My condition would be something like while time != timeEnd where timeEnd would be the value of below:
>>> timeEnd = datetime.datetime(2013, 12, 9, 21+N, 50, 32, 405329)
Thanks
解决方案You can add a timedelta to a datetime to get a new datetime.
>>> import datetime >>> now = datetime.datetime.now() >>> end_time = now + datetime.timedelta(hours=6) >>> print now 2013-12-09 17:03:06.979628 >>> print end_time 2013-12-09 23:03:06.979628 >>>Then...
while datetime.datetime.now() < end_time: pass # do work
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