我试图获得101个电话 - 产品目录TXT.txt.gz
有什么想法吗?
编辑:好吧我找到了解决方案...我的数组中的变量有值不能看到...正在做 $ b $ $ $ $ $ $ $ $ $ $输出= preg_replace('/ [^(\x20-\x7F) ] * /','',$ output); echo($ output);
清理并使其正常工作
解决方案doc http:// php/manual/en/control-structures.foreach.php 清楚地说明了为什么你有一个问题: 为了能够直接修改循环中的数组元素在$ value之前用& ;.在这种情况下,值将由引用赋值。
<< ;?php $ arr = array(1,2,3,4); foreach($ arr as& $ value){ $ value = $ value * 2; // $ arr现在是数组(2,4,6,8) unset($ value); //用最后一个元素?>来分隔引用。引用$ value是唯一可能的,如果迭代数组可以被引用(即,如果它是一个变量) 。以下代码将无效:
<?php / **这不起作用/ foreach(array(1,2,3,4)为& $ value){ $ value = $ value * 2; } ?>
Why does this yield this:
foreach( $store as $key => $value){ $value = $value.".txt.gz"; } unset($value); print_r ($store); Array ( [1] => 101Phones - Product Catalog TXT [2] => 1-800-FLORALS - Product Catalog 1 )I am trying to get 101Phones - Product Catalog TXT.txt.gz
Thoughts on whats going on?
EDIT: Alright I found the solution...my variables in my array had values I couldn't see...doing
$output = preg_replace('/[^(\x20-\x7F)]*/','', $output); echo($output);Cleaned it up and made it work properly
解决方案The doc php/manual/en/control-structures.foreach.php clearly states why you have a problem:
"In order to be able to directly modify array elements within the loop precede $value with &. In that case the value will be assigned by reference."
<?php $arr = array(1, 2, 3, 4); foreach ($arr as &$value) { $value = $value * 2; } // $arr is now array(2, 4, 6, 8) unset($value); // break the reference with the last element ?>Referencing $value is only possible if the iterated array can be referenced (i.e. if it is a variable). The following code won't work:
<?php /** this won't work **/ foreach (array(1, 2, 3, 4) as &$value) { $value = $value * 2; } ?>
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更改foreach循环内的值不会更改正在迭代的数组中的值
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