为什么我从 sql-server 得到以下结果?
Why I get following results from sql-server?
SELECT '' + 12 C1, CONVERT(int, '') C2, CASE WHEN '' = ' ' THEN 'equal' ELSE 'not equal' END C3Sql-Server Fiddle 演示
--Results | C1 | C2 | C3 | ------------------- | 12 | 0 | equal |C3 已得到答复.每个人都回答认为 '' + 12 = 12 是字符串连接,但它是一种数学运算.目前尚不清楚为什么(NOT 如何)'' 在 sql-server 中转换为 0.
C3 has been answered. Everyone answered thinking '' + 12 = 12 is string concatenation but it is a mathematical operation. It is not clear why (NOT how) '' is converting to a 0 in sql-server.
推荐答案SQL Server 有一个奇怪的特性,如果比较两个字符串,并且它们的长度不相等,那么它会将较短的一个填充到较长的一个,然后比较它们.填充字符是一个空格.support.microsoft/kb/316626
SQL Server has a strange feature whereby, if two strings are compared, and they are not of equal length, then it will pad the shorter one to the length of the longer one and then compare them. The padding character is a space. support.microsoft/kb/316626
C1 &C2 只是隐含的 &将空字符串显式转换为 0.
C1 & C2 are just implicit & explicit conversion of an empty string to 0.
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